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faltersainse [42]
3 years ago
6

Which best describes hooke’s equation?

Physics
2 answers:
Anit [1.1K]3 years ago
4 0

Answer:

B.

The explanation of the relationship between load and extension is not in Hooke's Law.

Explanation:

Lynna [10]3 years ago
3 0

Answer:

theory

Explanation:

I just took the test! hope this helps!

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FIRST TO ANSWER CORRECTLY GETS BRAIBLIEST!!
WINSTONCH [101]
Brushes, battery terminals, commutator, armature, magnets
7 0
2 years ago
What is the resistance of al lamp that allows a current of 10 amps with 120 volts
BartSMP [9]
V=ir
I=10
v=120
r=?
r=v/i
r=120/10
r=12 ohm
5 0
3 years ago
Two objects of equal mass collide on a horizontal frictionless surface. Before the collision, object A is at rest while object B
fenix001 [56]

Answer: 6m/s

Explanation:

Using the law of conservation of momentum, the change in momentum of the bodies before collision is equal to the change in momentum after collision.

After collision, the two objects will move at the same velocity (v).

Let mA and mB be the mass of the two objects

uA and uB be their velocities before collision.

v be their velocity after collision

Since the two objects has the same mass, mA= mB= m

Also since object A is at rest, its velocity = 0m/s

Velocity of object B = 12m/s

Mathematically,

mAuA + mBuB = (mA+mB )v

m(0) + m(12) = (m+m)v

0+12m = (2m)v

12m = 2mv

12 = 2v

v = 6m/s

Therefore the speed of the composite body (A B) after the collision is 6m/s

7 0
3 years ago
A bike rider was moving to the right at a constant speed. Suddenly the wind then starts blowing against her with 3 N of force to
stiks02 [169]

Answer:

The correct option is D

Explanation:

This question can be better understood when discussed using the Newton's first law of motion which states that an object would continue to move with a uniform speed (in a straight line) unless acted upon by an external force. What happens here (in the question) is that the bike rider would have continued moving at a constant speed (to the right) if not for the opposing force of the wind that acted against her (to the left). <u>This wind/force would cause her speed to reduce or slow down (as posited by the law)</u>.

8 0
3 years ago
• How much work is<br>required to lift a 2kg<br>object 2m high?<br>​
pychu [463]

Answer You need to consider that the gravity on earth is 9.8 m/s/s. This means any object you let go on the earths surface will gain 9.8 m/s of speed every second. You need to apply a force on the object in the opposite direction to avoid this acceleration. If you are pushing something up at a constant speed, you are just resisting earths acceleration. The more massive and object is, the greater force is needed to accelerate it. The equation is Force = mass*acceleration. So for a 2kg object in a 9.8 m/s/s gravity you need 2kg*9.8m/s/s = 19.6 Newtons to counteract gravity. Work or energy = force * distance. So to push with 19.6 N over a distance of 2 meters = 19.6 N*2 m = 39.2 Joules of energy. There is an equation that puts together those two equations I just used and it is E = mgh

The amount of Energy to lift an object is (mass) * (acceleration due to gravity) * (height)

:Hence, the Work done to life the mass of 2 kg to a height of 10 m is 196 J. Hope it helps❤️❤️❤️

Explanation:

7 0
3 years ago
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