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Vedmedyk [2.9K]
3 years ago
12

The magnetic bearing of compass "north" is _____. 090 180 270 360

Physics
1 answer:
MrMuchimi3 years ago
6 0
In navigation bearing refers to : 1. the direction of motion itself; 2. the direction of a distant object relative to the current course 3.the angle away from North of a distant point as observed at the current point.

There is a thing called absolute bearing, and it refers to the angle between the magnetic North/true North and an object. (e.g. an object of 0 degrees would be dead ahead, whereas and object of 180 degrees would be behind you)
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7. What is the velocity of an object with a distance of 90m south and a time of<br> 5s?
IrinaK [193]

Answer:

Explanation:

v= s/t

V =90m/5s

V = 8m/s

4 0
2 years ago
What term is used to describe all of the wavelengths of light waves?
Aneli [31]

Answer:

B.electromagnetic spectrum

Explanation:

Electromagnetic spectrum is used to  describe all of the wavelengths of light waves.Generally wavelength of the wave is denoted by λ.

Wavelength is the distance between two consecutive crest .Wavelength of the red color is minimum and wavelength of the violet color is maximum in the light  spectrum.

So the answer is B.

Electromagnetic spectrum

3 0
2 years ago
How do liquids affect friction?
Sophie [7]

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6 0
3 years ago
"Calculate the speed of this sound wave by recording how much time it takes to travel 5 meters. Use the (old school) velocity eq
lianna [129]
1) sound velocity reported by you : 292.39 m /s

2) time to travel 1620m at that velocity: t = d / v = 1620 m / 292.39 m/s = 5.54 s, since the moment the sound wave started.

3) You might wanted to tell the time since you watched the lightning.

Then you can calculate the time since the lighting was generated,1620 m away from you, until you saw it, using the speed of light:

 speed of light = 3*10^8 m/s => t = 1620 m / (3*10^8m/s) =0.0000054 s

Then, this time is completely neglectible, and yet the answer is 5.54 s, as calculated in the step 2.
7 0
3 years ago
A sled travels 15 meters down a slope inclined at 30 degrees with a horizontal. What is the horizontal displacement of the sled?
Arte-miy333 [17]

Length of the slope is given as

L = 15 m

also the inclination is given as

\theta = 30 degree

now the horizontal displacement is let say "x"

now from geometry we can say

\frac{x}{L} = cos30

x = L cos30

now substitute all values in it

x = 15 * cos30

x = 12.99 m

<em>so it will displace horizontally by 12.99 m</em>

6 0
3 years ago
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