Answer:
the final temperature of the tea is 7.39⁰C.
Explanation:
Given;
mass of the tea, m = 375 g
specific heat capacity of the tea, C = 4.184 JJ/g°C
initial temperature of the tea, t₁ = 95°C
the final temperature of the tea, t₂ = ?
Energy lost by the refrigerator, Q = 137,460 J
The energy lost by the refrigerator is given by the following formula;
-Q = mc(t₂ - t₁)
-137,460 =375 x 4.184(t₂ - 95°C)
-137,460 = 1569(t₂ - 95°C)
![t_2-95 = \frac{-137,460}{1569} \\\\t_2-95 = -87.61\\\\t_2 = -87.61 + 95\\\\t_2 = 7.39 \ ^0 C](https://tex.z-dn.net/?f=t_2-95%20%3D%20%5Cfrac%7B-137%2C460%7D%7B1569%7D%20%5C%5C%5C%5Ct_2-95%20%3D%20-87.61%5C%5C%5C%5Ct_2%20%3D%20-87.61%20%2B%2095%5C%5C%5C%5Ct_2%20%3D%207.39%20%5C%20%5E0%20C)
Therefore, the final temperature of the tea is 7.39⁰C.