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mr_godi [17]
4 years ago
8

Which is true about inelastic collisions: a. An inelastic collision does not obey conservation of energy. b. An inelastic collis

ion conserves kinetic energy. c. Objects will stick together upon collision. d. Momentum is not conserved in inelastic collisions..
Physics
1 answer:
Phoenix [80]4 years ago
5 0

Answer:

Option c is correct

Explanation:

There are two types of collisions-elastic collision and inelastic collision.

In elastic collision, both kinetic energy and total momentum are conserved. On the other hand, in inelastic collision, total momentum is conserved but kinetic energy is not conserved. Thus, option b and d are incorrect.

Total energy is always conserved in both types. Thus, option a is incorrect.

In a perfectly inelastic collision, objects stick together. This happens because maximum kinetic energy is dissipated and used in bonding of the two objects. Thus, correct option is c.

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A particle is moving in a circular path of radius r . The displacement after half a circle would be
Art [367]

Answer:

2r

Explanation:

As we know that

The displacement is the total distance measured between the initial or start and final or destination point

If particle cover half path of the circle, the displacement can easily find out by considering the distance between the start and destination point

We attached the diagram for better understanding

As per the diagram.

The displacement after half-circle is

AB = OA + OB

= r + r

= 2r

3 0
4 years ago
A proton travels with a speed of 1.8×106 m/s at an angle 53◦ with a magnetic field of 0.49 T pointed in the +y direction. The ma
Likurg_2 [28]

Answer:

Magnetic force, F=1.12\times 10^{-13}\ N

Explanation:

It is given that,

Velocity of proton, v=1.8\times 10^6\ m/s

Angle between velocity and the magnetic field, θ = 53°

Magnetic field, B = 0.49 T

The mass of proton, m=1.672\times 10^{-27}\ kg

The charge on proton, q=1.6\times 10^{-19}\ C

The magnitude of magnetic force is given by :

F=qvB\ sin\theta

F=1.6\times 10^{-19}\ C\times 1.8\times 10^6\ m/s\times 0.49\ Tsin(53)

F=1.12\times 10^{-13}\ N

So, the magnitude of the magnetic force on the proton is 1.12\times 10^{-13}\ N. Hence, this is the required solution.

3 0
3 years ago
Nuclear fusion is the combining of atomic nuclei to produce energy and
GenaCL600 [577]

Answer:

D) Radiation

Explanation:

Nuclear fusion is the combining of atomic nuclei to produce energy and radiation.

5 0
3 years ago
Electricity problem (coulomb's law)
ICE Princess25 [194]
Coulomb's Law: The interaction between charged objects is a non-contact force that acts over some distance of separation.
7 0
4 years ago
Calculate the force of gravity on the 0.50-kg mass if it were 6.4×106 m above earth's surface (that is, if it were two earth rad
Sunny_sXe [5.5K]

Radius of Earth is given as

R = 6.4 * 10^6 m

now here the height from the surface of earth is same as that of radius

h = 6.4 * 10^6 m

now here the acceleration due to gravity at this height is given as

g' = \frac{GM}{(R+h)^2}

g' = \frac{GM}{4R^2}

g' = \frac{g}{4}

now the force of gravity on the given object will be

F = mg'

F = m*\frac{g}{4}

F = 0.5 * \frac{9.8}{4}

F = 1.225 N

<em>so the force of gravity on it is 1.225 N</em>

7 0
3 years ago
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