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Lelechka [254]
3 years ago
15

Suppose you increase your walking speed from 7 m/s to 11 m/s in a period of 1 s. What is your acceleration?

Physics
1 answer:
QveST [7]3 years ago
6 0
Your acceleration would be four
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Velocity v (m/s)
Sonja [21]

Explanation:

given solution

h=45m v^2=u^2+2gh

g=10m/s^2 v^2=0^2+2×10m/s^2×45m

vi=0 v^2=900m^2/s^2

  • v=30
3 0
3 years ago
Pls a good 6th grade science project pls I will give you a lot of points
Scrat [10]

Answer:

you do a chemical reaction thing

Explanation:

get baking soda and mix it with b

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3 years ago
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A paper airplane with mass 0.1 kg is flying 1.5 m above the ground with a speed of 2 m/s. What is the total mechanical energy of
Wewaii [24]
Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
E = ½(0.1 kg)(2 m/s)² + (0.1 kg)(9.8 m/s²)(1.5 m)
E = 0.2 J + 1.47 J
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7 0
3 years ago
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The place where things are pushed together is.. <br><br> (Plz help me, I’m in a quiz)
kogti [31]
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3 years ago
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A light horizontal spring has a spring constant of 138 N/m. A 3.35 kg block is pressed against one end of the spring, compressin
BARSIC [14]

Answer:

U_k = 0.113

Explanation:

using the law of the conservation of energy:

E_i -E_f=W_f

\frac{1}{2}Kx^2=NU_kd

where K is the spring constant, x is the spring compression, N is the normal force of the block, U_k is the coefficiet of kinetic friction and d is the distance.

Also, by laws of newton, N is calculated by:

N = mg

N = 3.35 kg * 9.81 m/s

N = 32.8635

So, Replacing values on the first equation, we get:

\frac{1}{2}(138)(0.123)^2= (32.8635)U_k(0.281m)

solving for U_k:

U_k = 0.113

8 0
3 years ago
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