Answer:
s+s+s+s or s times 4
Step-by-step explanation:
The perimeter of a square is equal to 2l + 2w. In this case, 1l and 1w is equal to s. so 2(s) + 2(w) = 4s
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
<h3>Discriminant: </h3>
The quadratic formula includes the discriminant, which comes after the square root. The discriminant of a quadratic equation is important because it indicates the quantity and kind of solutions.
The formula for the Discriminant of a Quadratic Equation ax²+bx +c = 0 is given by
<h3> Discriminant Δ = b² - 4ac </h3>
Here we have
x² + 16x + c = 0 equation has only one real solution
Compare given equation with ax²+ bx + c = 0
=> a = 1, and b = 16
As we know when an equation has only one real solution
then its Discriminant will be equal to zero
=> b² - 4ac = 0
By the above values,
=> 16² - 4(1)c = 0
=> 256 - 4c = 0
=> 4c = 256
=> c = 256/4
=> c = 64
Therefore,
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
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The answer is anything that adds up to 7.
Examples: (5 + 2) or (3 + 4)
The rate of change is 25 because it goes 25 50 75 100 think of it like quarters
6? maybe 12 idk but its the best i could do
