Answer:
Needle and Scale Leaves. This kind of leaves are mostly found in 'evergreen' trees. ...
Lanceolate Leaf. ...
Oblong Leaf. ...
Linear Leaves. ...
Cordate Leaves.
Explanation:
Answer : The equilibrium concentration of
is, 0.50 M
Explanation : Given,
Initial moles of
= 0.65 mole
Volume of solution = 1.0 L
Moles of
at equilibrium = 0.15 mole
The balanced equilibrium reaction will be,

Initial moles 0.65 0 0
At eqm. (0.65-x) x x
Moles of
at equilibrium = x = 0.15 mole
Moles of
at equilibrium = x = 0.15 mole
Moles of
at equilibrium = (0.65-x) = (0.65-0.15) = 0.50 mole
Now we have to calculate the concentration of
at equilibrium.
Formula used : 



Therefore, the equilibrium concentration of
is, 0.50 M
Answer:
6 J
Explanation: Work done(J) = Force(N) × Distance(m) along the direction of force.
Given, Force=2 N, Distance=3 meters
∴ Wok done (J) = 2 × 3 = 6 J.
Answer: The correct option is C.
Explanation:
Oxidation reactions are a type of chemical reactions in which a substance looses electrons and forms positive charge. The substance undergoing this reaction is being oxidized.

Reduction reactions are a type of chemical reactions in which a substance gains electrons and forms negative charge. The substance undergoing this reaction is being reduced.

For the half reaction in which iron gains electrons means that iron is getting reduced.
Hence, the correct option is C.
Answer:
H+(aq) + OH-(aq) ⟶H2O(l)
Explanation:
Step 1: The balanced equation
HCN(aq) + KOH(aq) ⟶ H2O (l) + KCN (aq)
H+(aq) + CN-(aq) + K+(aq) + OH-(aq) ⟶H2O(l) + K+(aq) + CN-(aq)
Step 2: The net ionic equation
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:
H+(aq) + OH-(aq) ⟶H2O(l)