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vladimir2022 [97]
3 years ago
12

A gas is contained in a 5.0–liter container at a pressure of 100 kPa. What size container would be required to contain the gas a

t a pressure of 50 kPa, assuming the temperature remains constant?
Chemistry
1 answer:
Illusion [34]3 years ago
6 0
When volume and pressures are given, it means we need to use Boyles' law formula--> P1V1 = P2V2

P1= 100 kPa
V1= 5.0 L
P2= 50 kPa
V2= ???

let's plug in the values.

(100 x 5.0) = (50 x V2)

V2= 10 L
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Answer:

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Explanation:

For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>

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For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.

See figure 1

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2 years ago
Calculate the theoretical yield of 1-bromobutane; base your calculations on using 1.0 g of 1-butanol (as the limiting reagent).
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3 years ago
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Explanation:

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