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Mice21 [21]
3 years ago
6

A solution of 1.8274g of a polypeptide in 274mL of a aqueous solution has an osmotic pressure at 31.40 degrees C of 2.012 mmHg.

The approximate molecular weight of this polymer is _____ g/mol.
Chemistry
1 answer:
Airida [17]3 years ago
8 0

Answer: Hence, the approximate molecular weight of the poymer is 64106 g/mol

Explanation:

\pi=CRT

where,

\pi = osmotic pressure of the solution = 2.012 mm Hg =  0.0026 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (polypeptide) = 1.8274 g  

Volume of solution = 274 mL

R = Gas constant = 0.0821Latm/Kmol

T = temperature of the solution = 31.40^0C=(273+31.40)K=304.4K

Putting values in above equation, we get:

0.0026=\frac{1.8274 g\times 1000}{M\times 274ml}\times 0.0821\times 304.4

M=64106g/mol

Hence, the approximate molecular weight of the poymer is 64106 g/mol

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The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
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Explanation :  Given,

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Formula used :  

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where,

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