Let x be the number of days.
Daily pass:
65x + 30x
95x
Season pass:
400 + 30x
95x > 400 + 30x
65x > 400
x > 6.15
The number of days can't be 6.15, so you must round. You can't go down because then the price will be more expensive, so you have to round up.
It would take 7 days until the season pass is less expensive than the daily pass.
----------------------
You can check this by plugging in the x.
95x > 400 + 30x
95(7) > 400 + 30(7)
665 > 400 + 210
665 > 600
The daily pass is more expensive than the season pass.
Answer: 99.73%
Step-by-step explanation:
Given : Mean : 
Standard deviation : 
Let X be the random variable that represents the data values.
Formula for Z-score : 
For x=94, we have
For x=106, we have
The probability that the samples are between 94 and 106:-
Hence, the percent of the samples are expected to be between 94 and 106 = 99.73%
![\cfrac{\sqrt{36}\cdot 3^2-\sqrt[3]{-64}}{2^2}\implies \cfrac{\sqrt{6^2}\cdot 3^2-\sqrt[3]{(-4)^3}}{2^2}\implies \cfrac{6\cdot 3^2-(-4)}{2^2} \\\\\\ \cfrac{6\cdot 9-(-4)}{4}\implies \cfrac{54-(-4)}{4}\implies \cfrac{54+4}{4}\implies \cfrac{58}{4}](https://tex.z-dn.net/?f=%5Ccfrac%7B%5Csqrt%7B36%7D%5Ccdot%203%5E2-%5Csqrt%5B3%5D%7B-64%7D%7D%7B2%5E2%7D%5Cimplies%20%5Ccfrac%7B%5Csqrt%7B6%5E2%7D%5Ccdot%203%5E2-%5Csqrt%5B3%5D%7B%28-4%29%5E3%7D%7D%7B2%5E2%7D%5Cimplies%20%5Ccfrac%7B6%5Ccdot%203%5E2-%28-4%29%7D%7B2%5E2%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B6%5Ccdot%209-%28-4%29%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B54-%28-4%29%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B54%2B4%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B58%7D%7B4%7D)
notice, PEMDAS
groups first, then Exponents, then Multiplication and Division from left-to-right, then Addition and Subtraction from left-to-right last.
Step-by-step explanation:
<h3><u>Note</u>
: </h3>
The text below that are formatted in bold and underlined font are the solutions to the missing boxes in your given problem.
<h3><u>
Explanation:</u></h3>
Given that ∠1, ∠2, ∠3, and ∠4 are formed by two intersecting segments, and that:
∠1 and ∠2 form a linear pair
∠2 and ∠3 form a linear pair
These linear pair relationships suggest that by the Linear Pair Postulate:
<u>∠1 and ∠2 are supplementary</u>. ⇒ Linear Pair Postulate
<u>∠2 and ∠3 are supplementary</u>. ⇒ Linear Pair Postulate
m∠2 + m∠ 3 = 180° ⇒ <u>Definition of supplementary angles</u>.
<u>m∠1 + m∠3 = m∠2 + m∠ 3</u> ⇒ Substitution Property of Equality.
m∠1 = m∠3 ⇒ <u>Subtraction Property of Equality</u>.
