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FromTheMoon [43]
2 years ago
12

Given: measure 1, measure 2, measure 3, and measure 4 formed by two intersecting segments Prove: measure 1 and measure 3 are con

gruent. NEED HELP ASAP!!​

Mathematics
1 answer:
lesantik [10]2 years ago
4 0

Step-by-step explanation:

<h3><u>Note</u>: </h3>

The text below that are formatted in bold and underlined font are the solutions to the missing boxes in your given problem.  

<h3><u>Explanation:</u></h3>

Given that ∠1, ∠2, ∠3, and ∠4 are formed by two intersecting segments, and that:

∠1 and  ∠2 form a linear pair  

∠2 and ∠3 form a linear pair  

These linear pair relationships suggest that by the Linear Pair Postulate:

<u>∠1 and ∠2 are supplementary</u>.    ⇒  Linear Pair Postulate

<u>∠2 and ∠3 are supplementary</u>.    ⇒  Linear Pair Postulate

m∠2 + m∠ 3 = 180°  ⇒  <u>Definition of supplementary angles</u>.

<u>m∠1 + m∠3  = m∠2 + m∠ 3</u>  ⇒  Substitution Property of Equality.          

m∠1  =  m∠3   ⇒  <u>Subtraction Property of Equality</u>.  

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yulyashka [42]

Hey there! I'm happy to help!

The unit rate is how much stuff there is per 1 unit. All ratios can be rewritten as fractions, this one could be 0.2/0.5. The word per means divide, and fractions are basically dividing. So, we want the denominator to be 1.

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Have a wonderful day! :D

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