Answer:
$ 1.1
Explanation:
From the question given above, the following data were obtained:
Cost per kWh = $ 0.1
Current (I) = 10 A
Voltage (V) = 220 V
Time (t) = 5 h
Cost of operation =?
Next, we shall determine the power the electric oven. This can be obtained as follow:
Current (I) = 10 A
Voltage = 220 V
Power (P) =?
P = IV
P = 10 × 220
P = 2200 W
Next, we shall convert 2200 W to KW. This can be obtained as follow:
1000 W = 1 KW
Therefore,
2200 W = 2200 W × 1 KW / 1000 W
2200 W = 2.2 KW
Thus, 2200 W is equivalent to 2.2 KW.
Next, we shall determine the energy consumed by the electric oven. This can be obtained as follow:
Power (P) = 2.2 KW
Time (t) = 5 h
Energy (E) =?
E = Pt
E = 2.2 × 5
E = 11 KWh
Finally, we shall determine the cost of operation. This can be obtained as follow:
1 KWh cost $ 0.1
Therefore,
11 KWh will cost = 11 × 0.1
11 KWh will cost = $ 1.1
Therefore, the cost of operating the electric oven is $ 1.1
Solar system energy. electoral power engery motion force engery . wind energy. kinetic energy
Answer:
4.8 mph
Explanation:
From the question,
Average speed = total distance/total time
V = d/t....................... Equation 1
Where d = distance, t = time
Given: d = 26.2 miles, t = 5.5 hours.
Substitute these values into equation 1
V = 26.2/5.5
V = 4.76 mph
V ≈ 4.8 mph
Explanation:
According to newtons first law of motion " A body is at a state of rest or uniform motion unless acted upon by a force (external)" which will either
1. change the direction
2. change the acceleration
3. change the velocity(moves or stop the body from moving)
4. change the shape or size
