Ask question

Ask question

All categories

4 years ago

9

Drill bits are attached to power drills to make holes. Drill bits are made of {BLANK 1} because they’re hard and resistant to co

rrosion. The bodies and handles of power drills are made of {BLANK 2} because they’re good insulators.
BLANK 1
-Alloys
-Ceramics
-Composites

BLANK 2
-Alloys
-Composites
-Plastics

1 answer:

-BARSIC- [3]4 years ago

6 0

The correct answer is...

Drill bits are attached to power drills to make holes. Drill bits are made of Alloys because they’re hard and resistant to corrosion. The bodies and handles of power drills are made of Plastics because they’re good insulators.

You might be interested in

9. How much work is done when a 15kg box is lifted to a height of 2 meters?

torisob [31]

Answer: W = 294 J

Explanation: Solution:

Work is expressed as the product of force and the distance of the object.

W = Fd where F = mg

W= Fd

= mg d

= 15 kg ( 9.8 m/s²) ( 2m )

= 294 J

5 0

4 years ago

A race car starting from rest accelerates uniformly at 4.9 m/s^2. What is the car's speed after it has traveled 200 meters?

NeX [460]

The equation v²=u²+2as will help with solving this equation
v is what we are trying to find
u=0
a=4.9
s=200
v²=0²+2*4.9*200
v=√(2*4.9*200)
v=√1960
v=44.3 m/s (3 sf)

5 0

4 years ago

Read 2 more answers

A rocket has landed on Planet X, which has half the radius of Earth. An astronaut onboard the rocket weighs twice as much on Pla

Burka [1]

Explanation:

Let acceleration due to Gravity for a planet is given by:

$g_X=GM/R^2$

Here, $g_X = 2g$

Escape velocity is given by:

$v =\sqrt{ \frac{2GM} {R}} = \sqrt{2aR}$

Here, $R=R_earth/2$

and g_X = 2g

Therefore, $v=\sqrt(2(2g)(R/2))=v_0$

7 0

3 years ago

An electrician must decide between 3 heaters. The wire that she is using is rated 15A maximum, anything beyond that is a fire ha

lutik1710 [3]

Use the formula: $P=IV$ , where P is power (watts), I is current (amperes) and V is potential difference (volts).

For the first heater:
$900W = I_{1}*120V$
$I_{1} = 7.5A$

For the second heater:
$1800W = I_{2}*120V$
$I_{2} = 15A$

For the third heater:
$3000W = I_{3}*240V$
$I_{3} = 12.5A$

6 0

3 years ago

Three crates with various contents are pulled by a force Fpull=3615 N across a horizontal, frictionless roller‑conveyor system.

SIZIF [17.4K]

The question is incomplete. Here is the complete question.

Three crtaes with various contents are pulled by a force Fpull=3615N across a horizontal, frictionless roller-conveyor system.The group pf boxes accelerates at 1.516m/s2 to the right. Between each adjacent pair of boxes is a force meter that measures the magnitude of the tension in the connecting rope. Between the box of mass m1 and the box of mass m2, the force meter reads F12=1387N. Between the box of mass m2 and box of mass m3, the force meter reads F23=2304N. Assume that the ropes and force meters are massless.

(a) What is the total mass of the three boxes?

(b) What is the mass of each box?

Answer: (a) Total mass = 2384.5kg;

(b) m1 = 915kg;

m2 = 605kg;

m3 = 864.5kg;

Explanation: The image of the boxes is described in the picture below.

(a) The system is moving at a constant acceleration and with a force Fpull. Using Newton's 2nd Law:

$F_{pull}=m_{T}.a$

$m_{T}=\frac{F_{pull}}{a}$

$m_{T}=\frac{3615}{1.516}$

$m_{T}=2384.5$

Total mass of the system of boxes is 2384.5kg.

(b) For each mass, analyse each box and make them each a free-body diagram.

<u>For </u> $m_{1}$ <u>:</u>

The only force acting On the $m_{1}$ box is force of tension between 1 and 2 and as all the system is moving at a same acceleration.

$m_{1} = \frac{F_{12}}{a}$

$m_{1} = \frac{1387}{1.516}$

$m_{1}$ = 915kg

<u>For </u> $m_{2}$ <u>:</u>

There are two forces acting on $m_{2}$ : tension caused by box 1 and tension caused by box 3. Positive referential is to the right (because it's the movement's direction), so force caused by 1 is opposing force caused by 3:

$m_{2} = \frac{F_{23}-F_{12}}{a}$

$m_{2} = \frac{2304-1387}{1.516}$

$m_{2}$ = 605kg

<u>For </u> $m_{3}$ <u>:</u>

$m_{3} = m_{T} - (m_{1}+m_{2})$

$m_{3} = 2384.5-1520.0$

$m_{3}$ = 864.5kg

8 0

4 years ago