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3 years ago

8

In order to build a skyscraper Builders, Inc. hires 400 construction workers and 50 managers. Builders, Inc. represents A entrep

reneurship B land C capital D labor

1 answer:

laiz [17]3 years ago

7 0

Answer:A

Explanation:

You might be interested in

Write a program that uses the function isPalindrome given below. Test your program on the following strings: madam, abba, 22, 67

defon

Answer:

#include <iostream>

#include <string>

using namespace std;

bool isPalindrome(string str)

{

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

if (tolower(str[i]) != tolower(str[length - 1 - i]))

return false;

}

return true;

}

int main()

{

string s[6] = {"madam", "abba", "22", "67876", "444244", "trymeuemyrt"};

int i;

for(i=0; i<6; i++)

{

//Testing function

if(isPalindrome(s[i]))

{

cout << "\n " << s[i] << " is a palindrome... \n";

}

else

{

cout << "\n " << s[i] << " is not a palindrome... \n";

}

}

return 0;

}

5 0

3 years ago

Answer true or false 3.Individual people decide what will be produced in a command<br> oconomy

Pie

Answer:

False

Explanation:

The government decides the productions.

7 0

3 years ago

Read 2 more answers

At a certain location, wind is blowing steadily at 5 mph. Suppose that the mass density of air is 0.0796 lbm/ft3 and determine t

nlexa [21]

Answer:

The radius of a wind turbine is 691.1 ft

The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m

Explanation:

Given;

power generation potential (PGP) = 1000 kW

Wind speed = 5 mph = 2.2352 m/s

Density of air = 0.0796 lbm/ft³ = 1.275 kg/m³

Radius of the wind turbine r = ?

Wind energy per unit mass of air, e = E/m = 0.5 v² = (0.5)(2.2352)²

Wind energy per unit mass of air = 2.517 J/kg

PGP = mass flow rate * energy per unit mass

PGP = ρ*A*V*e

$PGP = \rho *\frac{\pi r^2}{2} *V*e \\\\r^2 = \frac{2*PGP}{\rho*\pi *V*e} , r=\sqrt{ \frac{2*PGP}{\rho*\pi *V*e}} = \sqrt{ \frac{2*10^6}{1.275*\pi *2.235*2.517}}$

r = 210.64 m = 691.1 ft

Thus, the radius of a wind turbine is 691.1 ft

PGP = CVᵃ

For best design of wind turbine Betz limit (c) is taken between (0.35 - 0.45)

Let C = 0.4

PGP = Cvᵃ

take log of both sides

ln(PGP) = a*ln(CV)

a = ln(PGP)/ln(CV)

a = ln(1000)/ln(0.4 *2.2352) = 7.73

The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m

5 0

2 years ago

4. The instant the ignition switch is turned to the start position,

geniusboy [140]

Answer:

D. Both pull-in and hold-in windings are energized.

Explanation:

The instant the ignition switch is turned to the start position, "Both pull-in and hold-in windings are energized." This is because the moment the ignition switch is turned to the start position, voltage passes through to the S terminal of the solenoid.

The hold-in winding is attached to the case of the solenoid. Similarly, the pull-in winding is also attached to the starter motor. Thereby, the current will move across both windings by getting energized to generate a strong magnetic field.

4 0

2 years ago

How will the delay and active power per device change as you increase the doping density of both the N- and the P-MOSFET?

Murljashka [212]

Answer:

hello your question is incomplete attached below is the missing part of the question

Consider an inverter operating a power supply voltage VDD. Assume that matched condition for this inverter. Make the necessary assumptions to get to an answer for the following questions.

answer : Nd ∝ rt

Explanation:

Determine how the delay and active power per device will change as the doping density of N- and P-MOSFET increases

Pactive ( active power ) = Efs * F

Pactive = $\frac{q^2Nd^2*Xn^2}{6Eo} * f$

also note that ; Pactive ∝ Nd2 (

tD = K . $\frac{Vdd}{(Vdd - Vt )^2}$ since K = constant

Hence : Nd ∝ rt

5 0

3 years ago