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gulaghasi [49]
3 years ago
12

What quantity measures the effect of change?

Engineering
2 answers:
alexandr1967 [171]3 years ago
8 0

Answer:

The Dependent Variable is the Effect, Its value depends on changes from the Independent Variable

Hope this Helps

Fed [463]3 years ago
4 0

Answer:

independent variable

Explanation:

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The term variation describes the degree to which an object or idea differs from others of the same type or from a standard.
AfilCa [17]
The answer is true. Thank me later<3
5 0
2 years ago
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A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane-strain fracture tough
jeyben [28]

Complete question:

A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture toughness of 98.9 MPa root m (90 ksi root in.) and a yield strength of 860 MPa (125,000 psi). The flaw size resolution limit of the flaw detection apparatus is 3.0 mm (0.12 in.). If the design stress is one-half of the yield strength and the value of Y is 1.0, determine whether or not a critical flaw for this plate is subject to detection.

Answer:

Since the flaw 17mm is greater than 3 mm the critical flaw for this plate is subject to detection

so that critical flow is subject to detection  

Explanation:

We are given:

Plane strain fracture toughness K = 98.9 MPa \sqrt{m}

Yield strength Y = 860 MPa

Flaw detection apparatus = 3.0mm (12in)

y = 1.0

Let's use the expression:

oc = \frac{K}{Y \sqrt{pi * a}}

We already know

K= design

a = length of surface creak

Since we are to find the length of surface creak, we will make "a" subject of the formula in the expression above.

Therefore

a= \frac{1}{pi} * [\frac{k}{y*a}]^2

Substituting figures in the expression above, we have:

= \frac{1}{pi} * [\frac{98.9 MPa \sqrt{m}} {10 * \frac{860MPa}{2}}]^2

= 0.0168 m

= 17mm

Therefore, since the flaw 17mm > 3 mm the critical flow is subject to detection  

3 0
3 years ago
Read 2 more answers
Determine the deflection at the center of the beam. Express your answer in terms of some or all of the variables LLL, EEE, III,
Rom4ik [11]

Answer:

See explanations for step by step procedures to get answer.

Explanation:

Given that;

Determine the deflection at the center of the beam. Express your answer in terms of some or all of the variables LLL, EEE, III, and M0M0M_0. Enter positive value if the deflection is upward and negative value if the deflection is downward.

4 0
3 years ago
In an ideal gas, specific enthalpy is a function of i. Entropy ii. Temperature iii, Pressure iv. Mass
Mice21 [21]

Answer:

Temperature

Explanation:

In an ideal gas the specific enthalpy  is exclusively a function of Temperature only this can be also written as h = h(T)  

A gas is said be ideal gas if obeys PV= nRT law

And in a ideal gas both internal energy and specific enthalpy are a function of Temperature only. Therefore the constant volume and constant pressure specific heats Cv and Cp are also function of temperature only.

5 0
3 years ago
A residential heat pump has a coefficient of performance of 1.49 How much heating effect, in kJ/h, will result when 4 kW is supp
AfilCa [17]

Answer:

21.456 kJ/h

Explanation:

See the figure attached. In this case  

W_{cycle} = 4 kW

Q_{out} = \text{heating effect}

Coefficient of performance in heat pump is defined by

COP = \frac{Q_{out}}{W_{cycle}}

Q_{out} =COP*W_{cycle}

Q_{out} =1.49*4 \, W

Q_{out} = 5.96 \, W

Now it is necessary to change units, remember that Watt (W) is defined as J/s

Q_{out} = 5.96 \frac{J}{s} \frac{3600s}{1 h} \frac{1 kJ}{1000 J}

Q_{out} = 21.456 \frac{kJ}{h}

3 0
3 years ago
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