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3 years ago

Rarefaction occurs only in a _______ wave.

Physics

2 answers:

natta225 [31]3 years ago

5 0

Answer:

1.B Longitudial

2.B air is cooler than the ground

Explanation:

Olenka [21]3 years ago

4 0

<u>Answers
</u>

1) B. longitudinal.

2) B. air is cooler than the ground.

<u>Explanation
</u>

There are two categories of a wave. That is transverse and longitudinal waves. Transverse waves forms crests and troughs while longitudinal forms compressions and rarefaction as they travel. Rarefactions are regions where the wavelengths are longer than other regions.

As the ray of light moves from an optically less dense to a more dense region it bends towards the normal.

If the sound is bending away from the earth's surface, then the ground must be warmer than the air. As the sound travels it moves from optically dense medium to a less dense medium. For this reason it bends away from the normal. This can only happen when, B. air is cooler than the ground.

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4 years ago

When a monochromatic light of wavelength 433 nm incident on a double slit of slit separation 6 µm, there are 5 interference frin

Bad White [126]

Answer:

The number of interference fringes is $n = 3$

Explanation:

From the question we are told that

The wavelength is $\lambda = 433 \ nm = 433 *10^{-9} \ m$

The distance of separation is $d = 6 \mu m = 6 *10^{-6} \ m$

The order of maxima is m = 5

The condition for constructive interference is

$d sin \theta = n \lambda$

=> $\theta = sin^{-1} [\frac{5 * 433 *10^{-9}}{ 6 *10^{-6}} ]$

=> $\theta = 21.16^o$

So at

$\lambda_1 = 632.9 nm = 632.9*10^{-9} \ m$

$6 * 10^{-6} * sin (21.16) = n * 632.9 *10^{-9}$

=> $n = 3$

4 0

3 years ago

Find the wavelength (in nm) of a 2.52 eV photon. a. 492.34127 nm.b. 585.88611 nm.c. 541.5754 nm.d. 418.49008 nm.

elena-14-01-66 [18.8K]

Answer:

The correct option is (a).

Explanation:

Given that,

The energy of photon, E = 2.52 eV

We need to find the wavelength of the photon in nm. The formula for the energy of a photon is given by :

$E=\dfrac{hc}{\lambda}\\\\\lambda=\dfrac{hc}{E}\\\\\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{2.52\times 1.6\times 10^{-19}}\\\\=4.93\times 10^{-7}\ m\\\\=493\ nm$

The nearest option is a) i.e. 492.34127 nm.

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3 years ago

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answer:

the first one

Explanation:

i think it is this one because 4k is bigger than 2k . also it is asking which one has the lager magnitude so it is the first one

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3 years ago

Which of the following is a device designed to open an overloaded circuit and prevent overheating?

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3 years ago