In the equation Y+2/y+1 + 2y^2-y+3/y^2-1 = y-2/y-1 the value of a is: a)2 b)1 c)4
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The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number
In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number
Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)
Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)
Let X be the number of times the die is rolled
The probability of getting a prime =
Now, the value of
E(X)=∑x.P(x) [ x-> {1, infinity}]
= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)
= 1. + 2.
.
+ 3.
.
+ 4.
.
.
.
.......
Hence, this is the value of E(x)
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