In the equation Y+2/y+1 + 2y^2-y+3/y^2-1 = y-2/y-1 the value of a is: a)2 b)1 c)4
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Answer: OPTION A.
Step-by-step explanation:
You can observe that in the figure CDEF the vertices are:
And in the figure C'D'E'F' the vertices are:
For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:
For C'(-8,-4) and C(-2,-1):
Let's choose another vertex. For E'(8,8) and E(2,2):
You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.
Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:
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