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klemol [59]
4 years ago
11

The maximum amount of pulling force a truck can apply when driving on

Physics
1 answer:
lina2011 [118]4 years ago
7 0

Answer:

Explanation:

Let the weight of the truck be W . reaction force R = W

Maximum frictional force = μ R

= .8 x W

So for movement of truck

Pulling force = frictional force

10560 = .8W

W = 13200 N

weight of heaviest truck required = 13200 N .

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1. A student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.
Snezhnost [94]

Explanation:

(a) Displacement of an object is the shortest path covered by it.

In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.  She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.

0.4 miles = 0.64 km

displacement = 0.7-0.3+0.64 = 1.04 km

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Hence, this is the required solution.

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4 years ago
Block 1, of mass m1 = 1.30 kg , moves along a frictionless air track with speed v1 = 27.0 m/s . It collides with block 2, of mas
Dennis_Churaev [7]

(A) The total initial momentum of the system is

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(B) Momentum is conserved, so that the total momentum of the system after the collision is

35.1 kg•m/s = (1.30 kg + 23.0 kg) <em>v</em>

where <em>v</em> is the speed of the combined blocks. Solving for <em>v</em> gives

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(C) The kinetic energy of the system after the collision is

1/2 (1.30 kg + 23.0 kg) (1.44 m/s)² ≈ 25.4 J

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1/2 (1.30 kg) (27.0 m/s)² ≈ 474 J

so that the change in kinetic energy is

∆<em>K</em> = 25.4 J - 474 J ≈ -449 J

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3 years ago
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Answer:

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Explanation:

4 0
3 years ago
Please HELP!!!!!!!!!!!!
Lunna [17]

Answer:

<em>If it served you, give me 5 stars please, thank you! </em>

<u>Muzzle velocity 300 m/s</u> corresponds to the .38 special

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