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4 years ago

You want to determine your speed running across the room. what is one piece of data you need

Physics

1 answer:

Reika [66]4 years ago

3 0

The distance you run divided by how long it takes

hope this is what you waned :)

You might be interested in

How are sports related to the concepts of force and motion?

crimeas [40]

Related to the force of motion,
Motion: Ability to move in a way of frequency.
Explanation: When we move in sport our bodies are more prone to motion and kinetic energy.

Hope this help :)

5 0

3 years ago

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charg

bekas [8.4K]

Answer:

$5.3\times 10^3 N/C$

Explanation:

We are given that

Distance between plates=d=2.2 cm= $2.2\times 10^{-2} m$

$1 cm=10^{-2} m$

$\sigma=47nC/m^2=47\times 10^{-9}C/m^2$

Using $1 nC=10^{-9} C$

We have to find the magnitude of E in the region between the plates.

We know that the electric field for parallel plates

$E=\frac{\sigma}{2\epsilon_0}$

$E_1=\frac{\sigma}{2\epsilon_0}$

$E_2=\frac{\sigma}{2\epsilon_0}$

$E=E_1+E_2$

$E=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}$

Where $\epsilon_0=8.85\times 10^{-12}C^2/Nm^2$

Substitute the values

$E=\frac{47\times 10^{-9}}{8.85\times 10^{-12}}$

$E=5.3\times 10^3 N/C$

Hence, the magnitude of E in the region between the plates= $5.3\times 10^3 N/C$

5 0

3 years ago

A 0.50-kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the a

marysya [2.9K]

Complete question:

A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.

Answer:

2.0N

Explanation:

Given that,

Mass, m of the frog = 0.5 kg

The acceleration of the frog = 4.0 m/s².

We have been asked To find,

The magnitude of the net force exerted on the frog as it leaps.

We calculate this using the formula below :

F = ma

When we insert the values into the formula, we have:

F = 0.5 kg × 4 m/s²

F = 2.0 N

Therefore, the magnitude of net force is 2.0 N.

5 0

3 years ago

10 points and brainlyest if possible and right.

Delicious77 [7]

THE answer the table is holding the book up would be a normal force

6 0

4 years ago

Your scores on the PFT will affect your grade<br> Question 1 options:<br> True<br> False

Valentin [98]

False it will not affect your grade

5 0

3 years ago