The approximate feed point impedance at the center of a two-wire folded dipole antenna will be 300 ohms.
<h3>What is impedance?</h3>
The combined effect of resistance and reactance in a circuit creates impedance, which opposes alternating current.
Consider the flat twin ribbon TV antenna wire with a 300 ohm impedance. A folded dipole's impedance is 4 times that of a half-wave dipole,
A folded dipole's impedance is found as;
Folded dipole's impedance = 4 × half-wave dipole
Half-wave dipole = 73 ohms
Folded dipole's impedance = 73 × 4
Folded dipole's impedance =292 ohms
Folded dipole's impedance ≈ 300 ohms.
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Answer:
= 3768 m/ms
Explanation:
For this exercise we will use the relationships of the moment
I = ∫ F dt = Δp
The expression for strength is
F = at - bt3
Let's replace and calculate the momentum
I = ∫ (at - bt3) dt
I = a t2 / 2 - b t4 / 4
We evaluate between the initial time of zero and the final time of 2.74 ms
I = ½ a (2.74)² - ¼ b (2.74)⁴
I = ½ 1500 7.51 - ¼ 20 56.36
I = 5632.5-281.8
I = 5350.7 N ms
Now we use the momentum relationship with the moment
I = Δp
I = m - m v₀
I = m - 0
= I / m
= 5350.7 / 1.42
= 3768 m / ms
= 3768 m / ms (1000 ms / 1 s) = 3.768 106 m / s
Answer:
I=
Explanation:
We are given that
Mass of rod=M
Length of rod=L
Mass of hoop=M
Radius of hoop=R
We have to find the moment of inertia I of the pendulum about pivot depicted at the left end of the slid rod.
Moment of inertia of rod about center of mass=
Moment of inertia of hoop about center of mass=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Answer
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Explanation: