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kvasek [131]
3 years ago
10

Your teacher gives you a black powder. When you dissolve the powder in water, you see red particles that float to the top, black

particles that sink to the bottom, and a green liquid. Was the black powder a pure substance, mixture, element, or compound? compound element pure substance mixture I think it is A
Chemistry
2 answers:
laila [671]3 years ago
3 0
The answer is B. A mixture can be separated as shown in the example.<span />
IgorC [24]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

A substance that cannot be broken down into simpler substances is known as an element.

For example, a piece of sodium metal contains only atoms of sodium.

Whereas a compound is defined as a substance that contains two different elements which are chemically combined together in a fixed ratio by mass.

For example, LiCl is a compound in which atoms are present in 1:1 ratio.

A compound is able to dissociate into its constituent particles but an element cannot.

Both an element and a compound are pure substances.

A mixture is defined as a substance in which two or more number of different substances are mixed together. Particles of a mixture never combine chemically to each other.

So, when black powder on coming in contact with water dissociates as red particles that float to the top, black particles that sink to the bottom, and a green liquid. Then it means a chemical reaction has taken place.

Hence, we can conclude that the black powder is a compound.

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9- Which pair of formulae represents two alkanes? (1 mark)
Ksenya-84 [330]

Answer:

A) CH4 and C8H18

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8 0
2 years ago
5.36 liters of nitrogen gas are at STP. What would be the new volume if we increased the moles from 3.5 moles to 6.0 moles?
Aleksandr [31]

Answer:

V_2=9.20L

Explanation:

Hello there!

In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:

\frac{V_2}{n_2}= \frac{V_1}{n_1}

In such a way, given the initial volume and both initial and final moles, we can easily compute the final volume as shown below:

V_2= \frac{V_1n_2}{n_1} \\\\V_2=\frac{5.36L*6.0mol}{3.5mol}\\\\V_2=9.20L

Best regards!

3 0
3 years ago
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