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Papessa [141]
3 years ago
6

What activity is considered a proper laboratory technique chem?

Chemistry
1 answer:
ale4655 [162]3 years ago
4 0

One of the activity of laboratory is the addition of acid to water.

The addition of acid to water make it easier for the reaction so that the acid gets diluted safely. On the other hand if water is added to acid it will get splash vigrously and may injure the hand of the chemist. The addition of water directly to acid contribute to exothermic reaction and releases more heat which may result in spraying around.

Adding acid to water, result in solution with very dilute solution and releases small heat. This small heat is not sufficient even to vaporizes a single drop of water.

Thus, adding acid to water is safer for dilution.


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An automobile tire was inflated to a pressure of 24 lb in-2 (1.00 atm = 14.7 lb in-2 ) on a winter’s day when the temperature wa
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Explanation:

Initial Pressure = 24 lb in-2

Initial Temperature = –5 o C = 268 K (Converting to kelvin temperature)

Final Pressure = ?

Final Temperature =  35 o C = 308 K (Converting to kelvin temperature)

No Change in Volume.

From Gay Lusaac's law; pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.

P1T1 = P2T2

P2 = P1T1 / T2

P2 = 24 * 268 / 308 = 20.88 lb in-2

There would be a drop in pressure as the temperature increases. Appropriate measures should b taken by regularly gauging the pressure of the tire.

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Round off 4.5778 x 10mg to three significant figures.
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Answer:

Explanation:

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What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of Al(OH)_3 = 0.610 g

Molar mass of Al(OH)_3 = 78 g/mol

\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

By Stoichiometry,

1 mole of  Al(OH)_3 reacts with 3 moles of HCl

So, 0.0078 moles of Al(OH)_3 will react with \frac{3}{1}\times 0.0078 = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

0.0234moles=\frac{\text{Given mass}}{36.5g/mol}

Mass of HCl required will be = 0.8541 grams

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