Answer is: her reasoning is flawed, because <span>Kc is very small, so the concentration of nitric(II) oxide is also very small. </span>
Balanced chemical reaction: N₂(g) + O₂(g) ⇄<span> 2NO(g).
</span>The equilibrium
constant<span> (Kc) is
a ratio of the concentration of the products (in this reaction nitrogen(II) oxide) to the concentration of the reactants (in this reaction nitrogen and oxygen):
</span>Kc = [NO]² / [N₂] · [O₂].
Kc = 4.7·10⁻³¹.
If we take equilibrium concentration of oxygen and nitrogen to be 1 M:
[N₂] = [O₂] = 1 M.
[NO] = √[N₂] · [O₂] · Kc.
[NO] = 6.855·10⁻¹⁶ M; equilibrium concentration of nitric oxide.
Answer:
n = 1.24 moles
Explanation:
Given that,
Mass = 153 grams
Molar mass of KClO₃ = 122.55 g/mol
We need to find the number of moles.
We know that,
No. of moles = given mass/molar mass
So,
So, there are 1.24 moles in 153 g of KClO₃.
Moving of positive charge electron and negative charge proton.
Explanation:
Correct option is
D
3
The unbalanced chemical reaction is Al(s)+O
2
(g)→Al
2
O
3
(s)
Balance Al atoms by adding 2 to Al on LHS
2Al(s)+O
2
(g)→Al
2
O
3
(s)
Balance O atoms by adding
2
3
to O
2
on LHS
2Al(s)+
2
3
O
2
(g)→Al
2
O
3
(s)
Multiply the whole equation with 2.
4Al(s)+3O
2
(g)→2Al
2
O
3
(s)
This is the balanced chemical equation. The coefficient of O
2
is 3.
Chemistry is the study of matter and the chemical reactions between substances.
hope this helps x
