Answer:
no picture you need add it
Answer:
Combustion reaction
2C2H6+7O2 → 4O2+6H2O
Explanation:
In a combustion reaction with a hydrocarbon in the reactant side you will always have O2 as another reactant. As you will always have CO2 and H2O as the products.
Knowing that much you can set up your reaction equation..
C2H6+O2→ CO2+H2O
Now the balancing can begin. Balancing hydrocarbon combustion reactions can be tricky, but if with practice they can be really fun and very rewarding.
Start with the C atoms first and move to the H atoms next. It's easier to leave the O2 to the last, it has a way to alter the equation.
Initially, you would arrive at this, before the O2 has been balanced:
C2H6+O2→2CO2+3H2O
But, as you can see, you have an odd amount of O2 on the product side. In this case, you have to find the common factor of the amount of O on the product side and 2, Because of the O2 diatom. Therefore, 14 would be the lowest common factor of 2 and 7.
I hope it helped you!
Answer:
c. fungi
Explanation:
Decomposers are organisms that breaks down dead and decaying matter in nature. They derived their nourishment by breaking down other complex organic matter.
Fungi are a group of organisms that are mainly decomposers.
They recyclers in nature.
Green plants and photosynthetic bacteria are similar in that they obtain nourishment by the use of light to initiate the reaction between carbon dioxide and water.
Many protists are decomposers but not all.
Answer:
1.62 × 10⁴ cal
Explanation:
Step 1: Given and required data
- Mass of water (m): 30.0 g
- Latent heat of vaporization of water (ΔH°vap): 540 cal/g
Step 2: Calculate the heat change (Q) for vaporization of 30.0g of water at 100 °C
The vaporization is a phase change in which water passes from the liquid state to the gaseous state. We can calculate the heat required using the following expression.
Q = ΔH°vap × m
Q = 540 cal/g × 30.0 g
Q = 1.62 × 10⁴ cal
