<h2>Answer :2PbSO4 → 2PbSO3 + O2 </h2>
Answer:
The weakest oxidizing agent is Zn^2+(aq)
The strongest reducing agent is Zn(s)
The strongest oxidizing agent is I2(s)
The weakest reducing agent is I^-(aq)
I^- cannot reduce Zn^2+ to Zn(s)
I2(s) can be reduced by hydrogen gas
Explanation:
In looking at oxidizing and reducing agents, our primary guide is the reduction potentials of each specie. The more negative the reduction potential of a specie, the better its function as a reducing agent. Zn has a very negative reduction potential hence it a very good reducing agent. Similarly, iodine has a very positive reduction potential hence it is a good oxidizing agent.
Only a specie having a more negative reduction potential than zinc can reduce it in aqueous solution. Similarly, the reaction potential of hydrogen is less than that of iodine hence hydrogen gas can reduce iodine.
Answer:
5.10¹¹ N/C
Explanation:
As we have a proton and a neutron, we can consider that they both have the same charge, this is:
e- = e+ = |1,6x10⁻¹⁹ C| , this number is in absolute value
Then, the formula needed to calculate the magnitude of the electric field from a charged particle is:
E= kqQ/r²
Where:
K= Coulomb constant
Q= charge
r = distance between two charges
Then:
E= 8.99x10⁹N/C²*(1.6x10⁻¹⁹C)/(5.3x10⁻¹¹m)²
E=5.12x1011 N/C
It is important that this value is a magnitude, it does not have any sign (positive or negative), for the magnetic field