Calculate the volume, in milliliters, for the following:
1 answer:
Answer: The volume for 0.850 mol of from a
solution is 1700 mL.
The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
Explanation:
Molarity is the number of moles of solute present in a liter of solution.
- As given moles of
are 0.850 mol and molarity of
Therefore, the volume for 0.850 mol of from a
solution is 1700 mL.
- As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.
So, volume for LiOH solution is calculated as follows.
Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
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Answer:
Explanation:
From the given information:
TO start with the molarity of the solution:
= 0.601 mol/kg
= 0.601 m
At the freezing point, the depression of the solution is
Using the depression in freezing point, the molar depression constant of the solvent
The freezing point of the solution
The molality of the solution is:
Molar depression constant of solvent X,
Hence, using the elevation in boiling point;
the Vant'Hoff factor
Answer : The partial pressure of at equilibrium is, 1.0 × 10⁻⁶
Explanation :
The partial pressure of =
The partial pressure of =
The partial pressure of =
The balanced equilibrium reaction is,
Initial pressure 1.0×10⁻² 2.0×10⁻⁴ 2.0×10⁻⁴
At eqm. (1.0×10⁻²-2p) (2.0×10⁻⁴+p) (2.0×10⁻⁴+p)
The expression of equilibrium constant for the reaction will be:
Now put all the values in this expression, we get :
The partial pressure of at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶
Therefore, the partial pressure of at equilibrium is, 1.0 × 10⁻⁶