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AleksandrR [38]
3 years ago
6

A cell using protein-mediated facilitated diffusion is treated with a toxin that prevents conformation change in the membrane pr

otein. What is the most likely outcome?
Chemistry
1 answer:
seraphim [82]3 years ago
3 0

Answer:

The most likely outcome is that carrier protein dysfunction will increase the gradient which will lead to disruption of cellular metabolism.

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How are humans releasing carbon dioxide into the air?
Gekata [30.6K]

Answer: A minor but very important component of the atmosphere, carbon dioxide is released through natural processes such as respiration and volcano eruptions and through human activities such as deforestation, land use changes, and burning fossil fuels.

Explanation:

5 0
4 years ago
Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21 ∘C∘C. Express the pressure
Volgvan

The question is incomplete, complete question is ;

A deep-sea diver uses a gas cylinder with a volume of 10.0 L and a content of 51.8 g of O_2 and 33.1 g of He. Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21°C.Express the pressures in atmospheres to three significant digits separated by commas.

Answer:

Partial pressure of the oxygen gas is 3.91 atm.

Partial pressure of the helium gas is 20.0 atm

Total pressure of the gases is 24.0 atm

Explanation:

Moles of oxygen gas = n_1=\frac{51.8}{32 g/mol}=1.619 mol

Moles of helium gas = n_2=\frac{33.1 g}{4 g/mol}=8.275 mol

Total moles of gas = n_1+n_2=(1.619 +8.275 ) mole=9.894 mol

Volume of the cylinder = V = 10.0 L

Total pressure in the cylinder = P = ?

Temperature of the gas in cylinder = T = 21°C = 21 + 273 K = 294 K

PV = nRT ( ideal gas equation )

P=\frac{nRT}{V}

=\frac{9.894 mol\times 0.0821 atm L/mol K\times 294 K}{10.0 L}

P = 23.88 atm ≈ 23.9

Partial pressure of the individual gas will be determined by the help of Dalton's law:

partial pressure = Total pressure × mole fraction of gas

Partial pressure of the oxygen gas

p_{1}=P\times \chi_{1}=P\times \frac{n_1}{n_1+n_2}

p_1=23.88 atm\times \frac{1.619 mol}{9.894 mol}=3.91 atm

Partial pressure of the helium gas

p_{2}=P\times \chi_{2}=P\times \frac{n_2}{n_1+n_2}

p_2=23.88 atm\times \frac{8.275 mol}{9.894 mol}=19.97 atm\approx 20.0 atm

6 0
4 years ago
What would happen to an atom in its ground state of external energy was applied to the electrons g
lisov135 [29]

Answer:

See explanation

Explanation:

According to Bohr's theory, when external energy is supplied to an atom, its electrons absorb energy and move from a lower energy level to a higher energy level.They quickly return to their original level and re-radiate the absorbed energy as a photo of light.

Hence, when an atom in ground state receives external energy, it becomes excited because energy is transferred to its electrons and they move from lower to higher energy level.

8 0
3 years ago
What is the half-life of sodium-25 if 1.00 gram of a 16.00-gram sample of sodium-25 remains unchanged after 237 seconds?
Readme [11.4K]
Given,
1 gram remain out of 16 grams after 237 seconds.

So, 
1g -> 2g -> 4g -> 8g -> 16g
So, 4 half lives have taken palce.

So,
we divide 237 by 4 and we get our answer.

So,
234 / 4 = 59.25 ≈ 59.3

So, the answer is (2) 59.3 seconds
8 0
3 years ago
The stopcock connecting a 4.87 L bulb containing hydrogen gas at a pressure of 4.38 atm, and a 4.87 L bulb containing argon gas
andrew-mc [135]

Answer:

P = 3,63 atm

Explanation:

Using PV=nRT and knowing the temperature in the problem remains constant it is possible to rewrite this formula, thus:

PV = kn, where k is RT (Constant), P is pressure, V is volume and n are moles.

The first bulb contains:

4,87L×4,38atm = 21,3k moles

And the second bulb:

4,87L×2,90atm = 14,1k moles

When gases are mixed, the total moles are:

21,3k moles + 14,1k moles = <em>35,4k moles</em>

As total volume is 4,87L + 4,87L = <em>9,74L</em>

Replacing:

P = kn/V

P = 35,4k moles / 9,74L

<em>P = 3,63 atm</em>

<em></em>

I hope it helps!

7 0
3 years ago
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