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Alex
3 years ago
12

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 8.60 MJ o

f energy (in the form of heat) if the temperature of the sodium is not to increase by more than 10.0 °C? Use CP= 30.8 J/(K·mol) for Na(l) at 500 K.
Chemistry
1 answer:
Alecsey [184]3 years ago
5 0

Answer: 64.216\times 10^4grams of liquid sodium is required.

Explanation: To calculate the mass of liquid sodium, we use the formula:

q=nc\Delta T\\q=\frac{m}{M}c\Delta T

where,

q = heat required, 8.60MJ=8.60\times 10^6J   (Conversion factor: 1MJ = 1000000J)

m = Mass of liquid sodium, ?g

M = Molar mass of liquid sodium, 23g/mol

c = Specific heat capacity, 30.8J/Kmol

\Delta T = change in temperature,  \Delta T=(510-500)K=10K    (Conversion factor: 0°C = 273K)

Putting values in above equation, we get:

8.60\times 10^6J=\frac{m}{23g/mol}\times 30.8J/Kmol\times 10K

m=64.216\times 10^4grams

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