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max2010maxim [7]
3 years ago
10

Be sure to answer all parts. Write an unbalanced equation to represent each of the following reactions: Do not include phase abb

reviations. (a) Nitrogen and oxygen react to form nitrogen dioxide. (b) Dinitrogen pentoxide reacts to form dinitrogen tetroxide and oxygen. (c) Ozone reacts to form oxygen. (d) Chlorine and sodium iodide react to form iodine and sodium chloride. (e) Magnesium and oxygen react to form magnesium oxide.
Chemistry
1 answer:
Eva8 [605]3 years ago
3 0

<u>Answer:</u> The unbalanced chemical equations are written below.

<u>Explanation:</u>

An unbalanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is not equal to the total number of individual atoms on the product side. These equations does not follow law of conservation of mass.

  • <u>For a:</u>

The chemical equation for the reaction of nitrogen gas and oxygen gas follows:

N_2+O_2\rightarrow NO_2

The product formed is nitrogen dioxide.

  • <u>For b:</u>

The chemical equation for the decomposition of dinitrogen pentaoxide follows:

N_2O_5\rightarrow N_2O_4+O_2

The product formed is dinitrogen tetroxide and oxygen gas.

  • <u>For c:</u>

The chemical equation for the reaction of ozone to oxygen gas follows:

O_3\rightarrow O_2

The product formed is oxygen gas.

  • <u>For d:</u>

The chemical equation for the reaction of chlorine and sodium iodide follows:

Cl_2+NaI\rightarrow NaCl+I_2

The product formed is sodium chloride and iodine gas

  • <u>For e:</u>

The chemical equation for the reaction of magnesium and oxygen gas follows:

Mg+O_2\rightarrow MgO

The product formed is magnesium oxide

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The state of matter that is most compressible is gases because it fits in anything it's put in
8 0
3 years ago
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What mass of CaCl2 (in g ) should the chemist use?
solmaris [256]

The mass of the solute required is 250.25 g.

<h3>What is the mass of the solute?</h3>

We know that the number of moles of the solute can be used to obtain the mass of the solute that is  required. We can now try to find the mass of the solute that is required.

Concentration of the solution = 0.350M

Volume of the solution = 6.5 L

Number of moles of the solute = 0.350M *  6.5 L

= 2.275 moles

We now have the mass of the solute as;

2.275 moles  * 110 g/mol

= 250.25 g

Th measured mass of the solute that we would have to use is 250.25 g.

Learn more about solute:brainly.com/question/7932885

#SPJ1

Missing parts;

A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?

3 0
1 year ago
the quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dis
Basile [38]

Answer:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

Explanation:

At a redox equation, one substance is being oxidized (losing electrons), and the other is being reduced (gaining electrons). In the given reaction:

BrO₃⁻(aq) + Sb³⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq)

When it's at an acidic solution, it must be ions H⁺ on the reactant, which will form water with the oxygen, so the complete reaction is:

BrO₃⁻(aq) + Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq) + H₂O(l)

As we can see, the antimony is being oxidized (go from +3 to +5), and the Bromo is being reduced. The oxidation number of brome in the reactant, knowing that the oxidation number of O is -2, is:

x + 3*(-2) = -1

x = +5

So, it's going from +5 to -1, and the half-reactions are:

BrO₃⁻(aq) + 6e⁻ → Br⁻(aq)

Sb³⁺(aq) → Sb⁵⁺(aq) + 2e⁻

The number of electrons must be the same, so the second equation must be multiplied by 3:

3Sb³⁺(aq) → 3Sb⁵⁺(aq) + 6e⁻

Thus, the equation will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + H₂O(l)

Now, we verify the amount of the elements, which must be equal on both sides. So, we multiply H₂O by 3, and H⁺ by 6, and the balanced reaction will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

6 0
4 years ago
A 7.028 gram sample of a sodium sulfate hydrate is heated. After driving off all the water, 3.100 grams of the anhydrous salt is
Nady [450]

Answer:

NaSO_4.10H_2O

Explanation:

Given that:-

Mass of the hydrated salt = 7.028 g

Mass of the anhydrous salt = 3.100 g

Mass of water eliminated = Mass of the hydrated salt - Mass of the anhydrous salt = 7.028 - 3.100 g = 3.928 g

<u>Moles of water: </u>

Mass of water = 3.928 g

Molar mass of H_2O = 18 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles are:

moles= \frac{3.928\ g}{18\ g/mol}

moles_{water}= 0.2212\ mol

<u>Moles of anhydrous salt: </u>

Amount = 3.100 g

Molar mass of NaSO_4 = 142.04 g/mol

Thus, moles are:

moles= \frac{3.100\ g}{142.04\ g/mol}

moles_{CaSO_4}= 0.02182\ mol

The simplest ratio of the two are:

NaSO_4:H_2O =0.02182 :  0.2212 = 1 : 10

<u>Hence, the formula for hydrate is:- NaSO_4.10H_2O</u>

7 0
3 years ago
The two isotopes of chlorine are 35/17 cl and 37/17cl. which isotope is the most abundant
Natalka [10]

The most abundant is 35/17 Cl

explanation

This is  because Chlorine  35/17 is the one close to the average atomic mass of chlorine which is  35.46 u making it to be the most abundant.

average atomic mass of chlorine is 35.46 + or- 0.02


7 0
3 years ago
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