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max2010maxim [7]
3 years ago
10

Be sure to answer all parts. Write an unbalanced equation to represent each of the following reactions: Do not include phase abb

reviations. (a) Nitrogen and oxygen react to form nitrogen dioxide. (b) Dinitrogen pentoxide reacts to form dinitrogen tetroxide and oxygen. (c) Ozone reacts to form oxygen. (d) Chlorine and sodium iodide react to form iodine and sodium chloride. (e) Magnesium and oxygen react to form magnesium oxide.
Chemistry
1 answer:
Eva8 [605]3 years ago
3 0

<u>Answer:</u> The unbalanced chemical equations are written below.

<u>Explanation:</u>

An unbalanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is not equal to the total number of individual atoms on the product side. These equations does not follow law of conservation of mass.

  • <u>For a:</u>

The chemical equation for the reaction of nitrogen gas and oxygen gas follows:

N_2+O_2\rightarrow NO_2

The product formed is nitrogen dioxide.

  • <u>For b:</u>

The chemical equation for the decomposition of dinitrogen pentaoxide follows:

N_2O_5\rightarrow N_2O_4+O_2

The product formed is dinitrogen tetroxide and oxygen gas.

  • <u>For c:</u>

The chemical equation for the reaction of ozone to oxygen gas follows:

O_3\rightarrow O_2

The product formed is oxygen gas.

  • <u>For d:</u>

The chemical equation for the reaction of chlorine and sodium iodide follows:

Cl_2+NaI\rightarrow NaCl+I_2

The product formed is sodium chloride and iodine gas

  • <u>For e:</u>

The chemical equation for the reaction of magnesium and oxygen gas follows:

Mg+O_2\rightarrow MgO

The product formed is magnesium oxide

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Answer:

The correct answer is option A.

Explanation:

Initial volume of the gas =V_1=3.5 L

Final volume of the gas = V_2=?

Initial pressure of the gas =P_1=0.8 atm

Final volume of the gas = P_2=0.5 atm

Using Boyle's law:

P_1V_1=P_2V_2

0.8 atm \times 3.5 L=0.5 atm\times V_2

V_2=5.6 L

Hence,the correct answer is option A.

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3 years ago
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Explanation:

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2 years ago
Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial conc
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Answer:

Ka = 4.76108

Explanation:

  • CO(g) + 2H2(g) ↔ CH3OH(g)

∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]

                      [ ]initial         change         [ ]eq

CO(g)              0.27 M       0.27 - x        0.27 - x

H2(g)              0.49 M       0.49 - x        0.49 - x

CH3OH(g)          0                0 + x               x = 0.11 M

replacing in Ka:

⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)

⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)

⇒ Ka = (0.11) / (0.38)²(0.16)

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7 0
3 years ago
Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.
insens350 [35]
Given:
Iron, 125 grams T
1 = 23.5 degrees Celsius, T2 = 78 degrees Celsius.  

Required:
Heat produced in kilojoules  

Solution:
The molar mass of iron is 55.8 grams per mole. SO we need to change the given mass of iron into moles.  
 
Number of moles of iron = 125 g/(55.8 g/mol) = 2.24 moles  
<span>
Q (heat) = nRT = nR(T2 = T1)</span>
Q (heat) = 2.24 moles (8.314 Joules per mol degrees Celsius) (78.0 degrees Celsius – 23.5 degrees Celsius)
<u>Q (heat) = 1014.97 Joules or 1.015 kilojoules</u> <span>This is the amount of heat produced in warming 125 g f iron.</span>
7 0
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3. Heating by direct contact between particles is called
Yanka [14]
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