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max2010maxim [7]
3 years ago
10

Be sure to answer all parts. Write an unbalanced equation to represent each of the following reactions: Do not include phase abb

reviations. (a) Nitrogen and oxygen react to form nitrogen dioxide. (b) Dinitrogen pentoxide reacts to form dinitrogen tetroxide and oxygen. (c) Ozone reacts to form oxygen. (d) Chlorine and sodium iodide react to form iodine and sodium chloride. (e) Magnesium and oxygen react to form magnesium oxide.
Chemistry
1 answer:
Eva8 [605]3 years ago
3 0

<u>Answer:</u> The unbalanced chemical equations are written below.

<u>Explanation:</u>

An unbalanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is not equal to the total number of individual atoms on the product side. These equations does not follow law of conservation of mass.

  • <u>For a:</u>

The chemical equation for the reaction of nitrogen gas and oxygen gas follows:

N_2+O_2\rightarrow NO_2

The product formed is nitrogen dioxide.

  • <u>For b:</u>

The chemical equation for the decomposition of dinitrogen pentaoxide follows:

N_2O_5\rightarrow N_2O_4+O_2

The product formed is dinitrogen tetroxide and oxygen gas.

  • <u>For c:</u>

The chemical equation for the reaction of ozone to oxygen gas follows:

O_3\rightarrow O_2

The product formed is oxygen gas.

  • <u>For d:</u>

The chemical equation for the reaction of chlorine and sodium iodide follows:

Cl_2+NaI\rightarrow NaCl+I_2

The product formed is sodium chloride and iodine gas

  • <u>For e:</u>

The chemical equation for the reaction of magnesium and oxygen gas follows:

Mg+O_2\rightarrow MgO

The product formed is magnesium oxide

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Snezhnost [94]

A substance that has no specific volume changes to a substance that has a specific volume.

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4 years ago
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Hafnium has six naturally occurring isotopes: 0.16% of 174Hf, with an atomic weight of 173.940 amu; 5.26% of 176Hf, with an atom
ser-zykov [4K]

Answer:

177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

Second isotope =175.941amu

Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

<em>Avera</em><em>ge</em><em> </em><em>ato</em><em>mic</em><em> </em><em>wei</em><em>ght</em><em> </em><em>of</em><em> </em><em>Haf</em><em>nium</em><em>=</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>the </em><em>atomi</em><em>c</em><em> </em><em>weights</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>iso</em><em>topes</em><em>/</em><em> </em><em>Tota</em><em>l</em><em> </em><em>occu</em><em>ring</em><em> </em><em>isotopes</em>

Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

Average atomic weight= 1063.661amu /6 = 177.2768333amu

= 177.277amu to 3 decimal places.

6 0
3 years ago
How many grams of Kr are in a 9.59 L cylinder at 46.0 'C and 4.62 atm?<br> mass:
Sladkaya [172]

Answer:

Mass = 141.6 g

Explanation:

Given data:

Mass of Kr in gram =  ?

Volume in L = 9.59 L

Temperature = 46.0°C

Pressure = 4.62 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

46.0+273 = 319 K

4.62 atm × 9.59 L = n× 0.0821 atm.L/ mol.K  ×319 K

44.3 atm.L = n×26.19 atm.L/ mol

n = 44.3 atm.L / 26.19 atm.L/ mol

n = 1.69 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1.69 mol × 83.79 g/mol

Mass = 141.6 g

8 0
3 years ago
How many grams of glucose are needed to form 150g of ethanol?
Svetradugi [14.3K]
<span>1 mole glucose gives 2 moles of ethanol

moles of glucose in 2.4 kg = 2400 / 180.18 = 13.320 moles

so moles of ethanol produced = 2* 13.32 = 26.64 moles

weight of ethanol 26.64 * 46.07

=1227.30 gm or 1.23 Kg</span>
6 0
3 years ago
PLEASE HELP ME ASAPPP!?
Brrunno [24]

lets guess and say #4???

7 0
3 years ago
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