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WITCHER [35]
3 years ago
5

A student is studying the effects of several solutions on the prevention of the browning of apples. the student used solutions h

aving different ph values and immersed three apple slices in equal volumes of each of the solutions. which of these is the independent variable in this investigation?
Chemistry
1 answer:
Olegator [25]3 years ago
4 0
Based on the variables that are used or stated on the problem, I think the independent variable in this investigation is the ph of the solution. Independent variable is a type of variable that is being manipulated in the experiment. Somehow, you are testing their effects on something. So base on the problem, the variable is being manipulated is ph of the solution. 
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How many moles of gas would you have if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature
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Answer: There are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

Explanation:

Given: Volume = 38.0 L

Pressure = 1430 mm Hg (1 mm Hg = 0.00131579 atm) = 1.9 atm

Temperature = 273.15 K

Using ideal gas equation, the moles of gas will be calculated as follows.

PV = nRT\\

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T =temperature

Substitute the values into above formula as follows.

PV = nRT\\1.9 atm \times 38.0 L = n \times 0.0821 L atm/mol K \times 273.15 K\\n = \frac{1.9 atm \times 38.0 L}{0.0821 L atm/mol K \times 273.15 K}\\= 3.2 mol

Thus, we can conclude that there are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

5 0
3 years ago
A 0.8838-g sample of an ionic compound containing bromide ions and an unknown metal cation is dissolved in water and treated wit
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3 years ago
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The half-life of gold-198 is 2.7 days. After
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Answer: 8.1 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant = x

a - x = amount left after decay process= \frac{x}{4} 

a) to find rate constant

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k=\frac{0.693}{2.7days}=0.257days^{-1}

b) for completion of one fourth of reaction

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t=\frac{2.303}{0.257}\log{4}

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8 0
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mr Goodwill [35]
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