Answer:
See explanation and image attached
Explanation:
The question has to do with the protonation of an alcohol. We know that oxygen has two lone pairs of electrons. Now a lone pair of electrons can pick up a proton leading to the formation of a coordinate bond between the proton and the oxygen atom.
The oxygen atom in the alcohol now has a positive charge as shown in the image attached to this answer. All the bonds remain single.
Answer:
Acceleration = (v Final −v Initial)/(t Final −t Initial). Where v stands for velocity and t stands for time. In algebraic notation, the formula can be expressed as: a=Δv/Δt; Acceleration can be defined as the rate of change of velocity with respect to time.
The phrase <em>"extremes are the </em><em>nemesis of habitability</em><em>" </em>as it refers to life space means that when things are not done in moderation, there tends to be danger for everyone in the habitat.
Habitation refers to a place where a group of people or organisms live.
As a result of this, we can see, when things are taken to extremes, such as when organisms struggle for food and other basic necessities, there will be a meltdown which can lead to the extinction of that specie in that particular habitat.
With this in mind, it is vital to keep things in moderation so that the organisms or people who live in that habitat can survive.
Read more here:
brainly.com/question/728057
Extensive: mass, length, volume
Inexpensive: color, density, aluminum
Answer:
See the answer and the resolution below
Explanation:
The equation of the decomposition of magnesium carbonate is as follows:
Mg C03 (white solid) ---> C02 (gas) + Mg= (solid)
To calculate the mass of carbon dioxide produced, the weight of 1 mol of this and 1 mol of MgC03 is calculated. Then a simple rule of 3 is made.
Weight 1 mol of MgC03= Weight Mg + Weight C+ 3x(Weight 0)= 24,305g+ 12,017+3x (15,999)= 84, 318g/mol
Weight 1 mol of C02= Weight C + 2x(Weight 0)=12,017+2x (15,999)= 44, 008g/mol
84, 319 g MgC03------44,008g C02
36,0 g MgC03------X= (36,0 g MgC03x44,008g C02)/84, 319 g MgC03= 18,8 g C02
