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sweet-ann [11.9K]
3 years ago
11

Which element does not have similar chemical characteristics as phosphorus (P)?

Chemistry
1 answer:
Trava [24]3 years ago
3 0
Generally (but far from universally), the elements within a group have similar characteristics. Antimony, nitrogen, and arsenic are all part of the same group as phosphorous (the pnictogens, or group 5A). Oxygen is not in this group, but rather in an adjacent group (the chalcogens, or group 6A). Thus, the answer here should be oxygen.

That said, there can be very significant differences in characteristics among the elements within a group, and that is certainly the case here. For example, free nitrogen exists predominantly as a molecular gas (N₂) and makes up about 78% of the atmosphere we breathe. Elemental arsenic (As), while in the same group as nitrogen, is naturally found in the solid state and is poisonous to humans (arsenic is sometimes included among the toxic heavy metals, although it’s technically a metalloid).
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Calculate the [OH-] given pH of 9.9
Juli2301 [7.4K]

Answer

pOH = 4.1

Explanation

<em>Given:</em>

pH = 9.9

<em>Required</em>: The concentration of OH-

Solution

pH + pOH = 14

9.9 + pOH = 14

pOH = 14-9.9

pOH = 4.1

3 0
1 year ago
Which statement best describes the domain and range of f(x) = -(7)X and g(x) = 7X7 O f(x) and g(x) have the same domain and the
Ivan

Answer:

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Explanation:

4 0
3 years ago
An iron bar of mass 841 g cools from 84°C to 7°C. Calculate the heat released (in kilojoules) by the metal.
Oduvanchick [21]

Answer:

28.75211 kj

Explanation:

Given data:

Mass of iron bar = 841 g

Initial temperature = 84°C

Final temperature = 7°C

Heat released = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

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ΔT = -77°C

By putting values,

Q = 841 g × 0.444 j/g.°C × -77°C

Q = 28752.11 j

In Kj:

28752.11 j × 1 kJ / 1000 J

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8 0
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sattari [20]
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Some examples of combustion are:

Fossil fuel:

Carbon + O2

C + O2 -> CO2

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Wood = cellulose = [C6H10O5]n

[C6H10O5]n + 6nO2 = 6n CO2 + 5n H2O

So, in general the combustion of organic matter produces CO2 and water.


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