Its work ability should be what you need<span />
Answer: Please see below for answers
Explanation: Matching appropriate labels , we have
1)3/4 of the way to second equivalence point of a diprotic acid/strong base titration-- pH=pka₂
equivalence point of a weak base/strong acid titration=pH<7
equivalence point of a strong acid/strong base titration= pH=7
equivalence point of a weak acid/strong base titration=pH>7
half-way to equivalence point of a weak acid/strong base titration pH =pka
where
pH gives the measure of the amount of concentration of hydrogen ions in an aqueous solution.
pKa is known as acid dissociation constant which explains the equilibrum at which a chemical species can give out or receive proton
pka₂ is the acid dissociation constant for the second ionization energy.
Answer:
c. 3
Explanation:
The unbalanced reaction expression is given as:
Fe + O₂ → Fe₂O₃
To balance the expression gives the coefficient of oxygen.
Assign the coefficients a,b, c and use a mathematical approach to solve this problem:
aFe + bO₂ → cFe₂O₃
Conserving Fe: a = 2c
O: 2b = 3c
Now let c = 1, a = 2, b =
Multiply through by 2,
a = 4, b = 3 and c = 2
4Fe + 3O₂ → 2Fe₂O₃
The coefficient of O₂ is 3
The statement that describes the chemical reaction is D chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromide<span>. The symbol "Cl" represents chlorine. The symbols in the brackets show the physical state of the substance, (g) is gaseous, (s) is solid, (aq) is aqueous and (l) is liquid.</span>
Answer:
5.55 L
Explanation:
This excersise can be solved by the Boyle's law.
This law for gases states that the pressure of a gas in a vessel is inversely proportional to the volume of the vessel.
P₁ . V₁ = P₂ . V₂
The law comes from the Ideal Gases Law, in the first term.
P . V = n . R . T In this case, n . R . T are all constant.
6.35 L . 88.6 kPa = 101.3 kPa . V₂
V₂ = (6.35 L . 88.6 kPa) / 101.3 kPa
V₂ = 5.55 L
It is inversely proportional because, as it happened in this case, pressure was increased, therefore volume decreased.