How many grams of NaCI are present in 11.00 moles
1 answer:
Answer: 642.93 g of NaCl
Explanation:
11.00 mol NaCl x __58.448 g__ = 642.928 g of NaCl
1 mol NaCl
I would round to 642.93 g of NaCl, but round to however many significant figures asked for.
My chemistry teacher made this map (image attached) to teach us how to do conversions. Just follow the map. I think it's pretty straight forward. I hope this helps.
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<u>Answer:</u> The amount of heat released is -7.203 kJ
<u>Explanation:</u>
The given chemical equation follows:
To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:
When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ
So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be
- To calculate the number of moles, we use the equation:
Given mass of hydrogen peroxide = 2.50 g
Molar mass of hydrogen peroxide = 34 g/mol
Putting values in above equation, we get:
- To calculate the heat of the reaction, we use the equation:
where,
= amount of heat released
n = number of moles = 0.0735 moles
= enthalpy change of the reaction = -98 kJ/mol
Putting values in above equation, we get:
Hence, the amount of heat released is -7.203 kJ