Calculate the density, in grams per liter, of carbon dioxide (CO2) gas at STP.
2 answers:
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Explanation:
It is known that each metal has a different work function and it is just the energy required to remove the electron from the surface.
The relation between energy and work function is as follows.
where, = energy of photon
Q = work function
K.E = kinetic energy of electron
When the value of Q is large then the amount of energy required by the photon is also large and vice-versa.
And, when there is not sufficient energy to remove an electron from metal surface or energy is less than its work function then electron will not be removed.
On the other hand, when incoming photon will have enough energy then electron will be ejected.
In the given situation, light from laser A is not able to remove the electron from metal surface which means that energy of photon is less than work function Q.
As, both B and C are able to remove electron from the surface of metal. So, after the removal of electrons rest of the energy of photons is transferred to eject electrons and this energy is converted into kinetic energy.
As energy of B is greater than the energy of C and A has the lowest energy among all.
Therefore, order of energy from lowest to highest is as follows.
A < C < B
Now, the relation between energy and wavelength is as follows.
E =
where, = wavelength
So, energy is inversely proportional to wavelength. Therefore, increase in energy means decrease in wavelength.
Therefore, increasing order of wavelength is as follows.
B < C < A
The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.
<h3>What is empirical formula?</h3>The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.
<h3>How to find the empirical formula?</h3>Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.
Moles phosphorus = 0.903 g phosphorus = 0.0293 mol
Moles bromine 6.99 g bromine=0.0875 mol
The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3
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