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3 years ago

Gamma radiation:

Chemistry

1 answer:

34kurt3 years ago

3 0

Answer:

All of the above

Explanation:

All given are the properties of gamma radiations. Because,

These can be detected with scientific instruments.

These radiations emitted with alpha or beta emission.

These radiations can penetrate to ma y other materials.

Gamma radiations:

Gamma radiations are high energy radiations having no mass.

These radiations are travel at the speed of light.

Gamma radiations can penetrate into the many materials.

These radiations are also used to treat the cancer.

Lead is used for the protection against gamma radiations because of its high molecular density.

The lead apron are used by the person when treated with gamma radiations.

Lead shields are also used in the wall, windows and doors of the room where gamma radiations are treated, in-order to protect the surroundings.

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Ammonia (NH3) ionizes according to the following reaction: NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH–(aq) The base dissociation constant

Ira Lisetskai [31]

Answer:

pH = 9.6

Explanation:

According to Brönsted-Lowry theory, NH₃ is a base and NH₄⁺ its conjugate acid. When they are together in a solution, the form a buffer, which is used to resist abrupt changes in pH when an acid or a base is added. pOH fro a buffer can be found using Henderson-Hasselbalch equation.

$pOH = pKb + log\frac{conjugateacid}{base}$

Since NH₄Cl is a strong electrolyte, [NH₄Cl] = [NH₄⁺]

$pOH = pKb + log\frac{[NH_{4}^{+} ]}{[NH_{3}]} =4.7+log\frac{0.035M}{0.070M} =4.4$

Now, we can find pH using the following expression:

pH + pOH = 14

pH = 14 - pOH = 14 - 4.4 = 9.6

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4 years ago

A solution has a pH of 1.98. What is the pOH of the solution?<br> CD

xz_007 [3.2K]

Answer:

12.02

Explanation:

pH + pOH =14

1.98 + pOH = 14

pOH = 14 - 1.98 = 12.02

6 0

3 years ago

How many grams of silver cholride will be precipitated by adding sufficient silver nitrate to react with 1500.0mL of.400M barium

Taya2010 [7]

Answer: 172.2 g of $AgCl$ is formed by adding sufficient silver nitrate to react with 1500.0mL of 0.400M barium chloride solution.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}={\text {Molarty}}\times {\text{Volume in L}}=0.400\times 1.5L=0.6moles$

$BaCl_2+2AgNO_3\rightarrow 2AgCl+Ba(NO_3)_2$

According to stoichiometry:

1 mole of $BaCl_2$ produce = 2 moles of $AgCl$

Thus 0.6 moles $BaCl_2$ will produce = $\frac{2}{1}\times 0.6=1.2$ moles of $AgCl$

Mass of $AgCl=moles\times {\text {molar mass}}=1.2mol\times 143.5g/mol=172.2g$

Thus 172.2 g of $AgCl$ is formed by adding sufficient silver nitrate to react with 1500.0mL of 0.400M barium chloride solution.

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3 years ago

What is an unconfined aquifer?

Firdavs [7]

Answer:

Unconfined aquifers are those into which water seeps from the ground surface directly above the aquifer. Confined aquifers are those in which an impermeable dirt/rock layer exists that prevents water from seeping into the aquifer from the ground surface located directly above.

Explanation:

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3 years ago

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Combustion of 5.024 mg of coniine yields 13.90 mg CO2 and 6.048 mg of H2O. What is the empirical formula for coniine, listing th

dimulka [17.4K]

Answer:

C8H17N

Explanation:

Number of moles of c

13.90 × 10^-3/44 g/mol × 1 = 0.000316 moles

Mass of C= 0.000316 moles × 12 = 0.00379 g

Number of moles of H

6.048 × 10^-3/18 × 2 = 0.000672 moles

Mass of H

0.000672 moles × 1 = 0.000672 g

Mass of N

0.005024 - [0.00379 g + 0.000672 g]

= 0.000562 g

Number of moles of N

0.000562 g/14 = 0.00004 moles

Divide through by the lowest ratio;

C= 0.000316/0.00004, H= 0.000672 /0.00004, N= 0.00004/0.00004

C= 8, H = 17, N = 1

Hence the empirical formula is;

C8H17N

3 0

3 years ago