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AURORKA [14]
3 years ago
8

5 shown here are cartoons of two different polymers. based on these cartoons, which polymer would you expect to be denser? which

one would have the higher melting point? [section 12.8]

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer: The correct answer for a) Linear polymer with high density and high melting point and b) branched polymer with low density and low melting point

As the image is not attached , so I think it should be following image .

In the image , there are two types of polymers present . One polymer is long an unbranched , while other polymer is short and branched .

Polymers : These are giant molecules or repeating chains of small molecules formed by linking small molecules together by Carbon- Carbon covalent bonds .They are also called as " Macro molecules " . The process of formation of polymers is known as polymerization . The small molecules or the repeating units of a polymer are known as Monomers.

Polymers are produced naturally and can be synthesized artificially . Example of natural polymer are proteins , DNA etc and Artificial polymer are polyethylene , backelite etc.

Polymers are of various type based on their structure , linear , branched , cross linked . ( Describing following types of polymers based on image )

A) Linear polymers : These are long straight chain polymers like long string of Carbon -Carbon chain . These polymers when form , they fold back themselves like strands of fibre or mesh . They form very strong polymers .

They have well packed structures, due to which they have high intermolecular force of attraction . These high intermolecular force of attraction provide them high tensile strength and high density and hence they will have high melting point . It will be very difficult to break them .

Examples : Polyethene [-CH₂-CH₂-]n

Hence it can be said that a) box contains linear polymers and have high melting points and low densities.

B) Branched Polymers : These are linear polymers but have branches at regular intervals . These branches are known as side chains . The branches can be small or very long group . Branches polymers are also known as Dendrimers.

Due to branching , they cannot be closely packed . Branching prevents chain from getting close enough or to pack closely . Due to which they have low intermolecular forces . Hence they have low density and low tensile strength .So they have low melting points as well .

Examples : Glycogen , starch etc .

Since in image b) we can see the polymers have mall branches they can be assigned as " Branched polymers " and they will have low melting points and low densities.

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Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH
Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

    No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{12 g}{60 g/mol}

                           = 0.2 mol

Molarity of acetic acid is calculated as follows.

              Density = \frac{mass}{volume}

                 1 g/ml = \frac{100 g}{volume}

                    volume = 100 ml

Hence, molarity = \frac{\text{no. of moles}}{volume}

                           = \frac{0.2 mol}{0.1 L}

                           = 2 mol/l

As reaction equation for the given reaction is as follows.

     NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O

So,          moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

          x \times 1 M = 10 mL \times 2 M     (as 1 L = 1000 ml)

                        x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.                    

6 0
3 years ago
Identify the mixture of powdered charcoal and powdered sugar and suggest a technique for separating their components
mihalych1998 [28]
A- Identify the mixture:
The mixture of powdered charcoal and powdered sugar is considered as a homogeneous mixture. This means that you cannot identify the components with naked eye as they are uniformly distributed in the mixture.

B- Separate components:
You ca separate the charcoal powder from the sugar powder using the following steps:
1- add water. Sugar will dissolve in water while charcoal won't.
2- filter the solution where the powdered charcoal will remain on the filter paper and the solution of powder will pass through.
3- boil the sugar solution (above 100 degrees celcius). The water will evaporate and the sugar will precipitate.
5 0
3 years ago
A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section
Sophie [7]

Each section would be 230 centimeters or 2.30 meters long.

<h3>Sectional division</h3>

The original wood pole is 12 meters long.

12 meters = 12 x 100 = 1200 centimeters

It is to be cut into 5 equal sections: 1200/5 = 240 centimeters

But each cut wastes 10 cm of the pole.

          240 - 10 = 230 centimeters.

Thus, each section would be 230 centimeters or 2.30 meters long.

More on sectional divisions can be found here: brainly.com/question/15381501

#SPJ1

6 0
2 years ago
A 25.00 ml solution of sulfuric acid H2SO4 is titrated to phenolphthalein end point with 27.00 ml of 1.700 M KOH
Nastasia [14]
<h3>Answer:</h3>

0.918 M

<h3>Explanation:</h3>

Assuming the question requires we calculate the Molarity of sulfuric acid:

We are given:

  • Volume of the acid, H₂SO₄ = 25.00 ml
  • Volume of the base, KOH = 27.00 mL
  • Molarity of the base, KOH is 1.70 M

We can calculate the molarity of the acid using the following steps;

<h3>Step 1: Write the chemical equation for the reaction.</h3>

The reaction is an example of a neutralization reaction where a base reacts with an acid to form salt and water.

Therefore, the balanced equation will be;

H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)

<h3>Step 2: Determine the moles of the base, KOH </h3>

When given molarity and the volume of a solution, the number of moles can be calculated by multiplying molarity with volume.

Number of moles = Molarity × Volume

                             = 1.700 M × 0.027 L

                              = 0.0459 moles

Thus, moles of KOH used is 0.0459 moles

<h3>Step 3: Determine the number of moles of the Acid, H₂SO₄</h3>

From the reaction, 1 mole of the acid reacts with 2 moles of KOH

Therefore, the mole ratio of H₂SO₄ to KOH is 1 : 2

Thus, moles of H₂SO₄ = Moles of KOH ÷ 2

                                     = 0.0459 moles ÷ 2

                                     = 0.02295 moles

<h3>Step 4: Calculate the molarity of the Acid </h3>

Molarity is the concentration of a solution in moles per liter

Molarity = Moles ÷ Volume

Molarity of the acid = 0.02295 moles ÷ 0.025 L

                                = 0.918 M

Thus, the molarity of the acid, H₂SO₄ is 0.918 M

5 0
3 years ago
Plz HElp!!!!
valentina_108 [34]

Answer:

Substance 4

Explanation:

Density is defined as mass per unit volume. A substance floats in another when its density is less than that of the substance on which it floats.

If an object is immersed in a denser liquid, it will sink

Since the density of water is 1 g/cm^3, any substance whose density is less than that of water will float in it.

If we look at the table, substance 4 has a density of 0.5g/cm^3. Hence, substance 4 is expected to float in water.

7 0
2 years ago
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