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AURORKA [14]
3 years ago
8

5 shown here are cartoons of two different polymers. based on these cartoons, which polymer would you expect to be denser? which

one would have the higher melting point? [section 12.8]

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer: The correct answer for a) Linear polymer with high density and high melting point and b) branched polymer with low density and low melting point

As the image is not attached , so I think it should be following image .

In the image , there are two types of polymers present . One polymer is long an unbranched , while other polymer is short and branched .

Polymers : These are giant molecules or repeating chains of small molecules formed by linking small molecules together by Carbon- Carbon covalent bonds .They are also called as " Macro molecules " . The process of formation of polymers is known as polymerization . The small molecules or the repeating units of a polymer are known as Monomers.

Polymers are produced naturally and can be synthesized artificially . Example of natural polymer are proteins , DNA etc and Artificial polymer are polyethylene , backelite etc.

Polymers are of various type based on their structure , linear , branched , cross linked . ( Describing following types of polymers based on image )

A) Linear polymers : These are long straight chain polymers like long string of Carbon -Carbon chain . These polymers when form , they fold back themselves like strands of fibre or mesh . They form very strong polymers .

They have well packed structures, due to which they have high intermolecular force of attraction . These high intermolecular force of attraction provide them high tensile strength and high density and hence they will have high melting point . It will be very difficult to break them .

Examples : Polyethene [-CH₂-CH₂-]n

Hence it can be said that a) box contains linear polymers and have high melting points and low densities.

B) Branched Polymers : These are linear polymers but have branches at regular intervals . These branches are known as side chains . The branches can be small or very long group . Branches polymers are also known as Dendrimers.

Due to branching , they cannot be closely packed . Branching prevents chain from getting close enough or to pack closely . Due to which they have low intermolecular forces . Hence they have low density and low tensile strength .So they have low melting points as well .

Examples : Glycogen , starch etc .

Since in image b) we can see the polymers have mall branches they can be assigned as " Branched polymers " and they will have low melting points and low densities.

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In the primary structure, the amino acids are linked by peptide bonds. That is, the order of the amino acids is the criterion that defines this type of structure.

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In the secondary structure, we have to look at the way in which the protein is folded. The options are:

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Suppose you have just added 100 ml of a solution containing 0.5 mol of acetic acid per liter to 400 ml of 0.5 m naoh. what is th
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pH = 13.5

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Sodium hydroxide completely ionizes in water to produce sodium ions and hydroxide ions. Hydroxide ions are in excess and neutralize all acetic acid added by the following ionic equation:

\text{HAc} + \text{OH}^{-} \to \text{Ac}^{-} + \text{H}_2\text{O}

The mixture would contain

  • 0.4 \times 0.5 - 0.1 \times 0.5 = 0.15 \; \text{mol} of \text{OH}^{-} and
  • 0.1 \times 0.5 = 0.05 \; \text{mol} of \text{Ac}^{-}

if \text{Ac}^{-} undergoes no hydrolysis; the solution is of volume 0.1 + 0.4 = 0.5 \; \text{L} after the mixing. The two species would thus be of concentration 0.30 \; \text{mol} \cdot \text{L}^{-1} and 0.10 \; \text{mol} \cdot \text{L}^{-1}, respectively.

Construct a RICE table for the hydrolysis of \text{Ac}^{-} under a basic aqueous environment (with a negligible hydronium concentration.)

\begin{array}{cccccccc} \text{R} & \text{Ac}^{-}(aq) &+ & \text{H}_2\text{O}(aq) & \leftrightharpoons & \text{HAc}(aq) & + & \text{OH}^{-} (aq)\\ \text{I} & 0.10 \; \text{M} & & & & & &0.30 \; \text{M}\\ \text{C} & -x \; \text{M}& & & & +x \; \text{M}& & +x \; \text{M} \\ \text{E} & (0.10 - x) \; \text{M} & & & & x \; \text{M} & & (0.30 +x) \; \text{M} \end{array}

The question supplied the <em>acid</em> dissociation constant pK_afor acetic acid \text{HAc}; however, calculating the hydrolysis equilibrium taking place in this basic mixture requires the <em>base</em> dissociation constant pK_b for its conjugate base, \text{Ac}^{-}. The following relationship relates the two quantities:

pK_{b} (\text{Ac}^{-}) = pK_{w} - pK_{a}( \text{HAc})

... where the water self-ionization constant pK_w \approx 14 under standard conditions. Thus pK_{b} (\text{Ac}^{-}) = 14 - 4.7 = 9.3. By the definition of pK_b:

[\text{HAc} (aq)] \cdot [\text{OH}^{-} (aq)] / [\text{Ac}^{-} (aq) ] = K_b =  10^{-pK_{b}}

x \cdot (0.3 + x) / (0.1 - x) = 10^{-9.3}

x = 1.67 \times 10^{-10} \; \text{M} \approx 0 \; \text{M}

[\text{OH}^{-}] = 0.30 +x \approx 0.30 \; \text{M}

pH = pK_{w} - pOH = 14 + \text{log}_{10}[\text{OH}^{-}] = 14 + \text{log}_{10}{0.30} = 13.5

6 0
3 years ago
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