Hello!
we put the a and y values into the equation
2(-6) - 4
2 * -6 = -12
-12 - 4 = -16
The answer is -16
Hope this helps!
Answer:
food A has fewer calories
Step-by-step explanation:
food b has 250 cal. in 2/3 of a serving and food a has only 150 in 3/4 of a serving, and because it is 3/4 we can know that the last amount of cal. in food a is 50, meaning that with all the calories in the full serving, it has less calories then food b with a fraction of the calories. food a is the answer
Answer:
How do you find the equilibrium price with a supply and demand function?
To determine the equilibrium price, do the following.
Set quantity demanded equal to quantity supplied:
Add 50P to both sides of the equation. You get.
Add 100 to both sides of the equation. You get.
Divide both sides of the equation by 200. You get P equals $2.00 per box. This is the equilibrium price.
Answer:
6π
Step-by-step explanation:
The period indicates after which time the sine wave repeats.
You divide 2π by the factor in front of your function variable. This is 1/3 for your function.
So 2π/(1/3) = 6π
Answer:
<u>88/345 which is 0.2551</u>
Step-by-step explanation:
Since we are picking 2 athletes randomly and without replacement.
Probability of 1 volleyball player = 24/46 = 12/23
Probability of basketball player (<u>this</u><u> </u><u>is</u><u> </u><u>aft</u><u>er</u><u> </u><u>1</u><u> </u><u>vol</u><u>ley</u><u>ball</u><u> </u><u>play</u><u>er</u><u> </u><u>has</u><u> </u><u>alr</u><u>eady</u><u> </u><u>be</u><u>en</u><u> </u><u>picked</u><u>)</u><u>.</u><u> </u><u>We</u><u> </u><u>hav</u><u>e</u><u> </u><u>4</u><u>5</u><u> </u><u>players</u><u> </u><u>left</u><u>.</u><u> </u><u>=</u><u> </u><u>2</u><u>2</u><u>/</u><u>4</u><u>5</u>
<u>proba</u><u>bility</u><u> </u><u>of</u><u> </u><u>picki</u><u>ng</u><u> </u><u>one</u><u> </u><u>volle</u><u>yball</u><u> </u><u>pla</u><u>yer</u><u> and</u><u> </u><u>one</u><u> </u><u>bask</u><u>e</u><u>tball</u><u> player</u>
<u>p</u><u>(</u><u>voll</u><u>eyball</u><u> </u><u>pla</u><u>yer</u><u> </u><u>a</u><u>nd</u><u> </u><u>bask</u><u>etball</u><u> </u><u>player</u><u>)</u>
<u>(</u><u>1</u><u>2</u><u>/</u><u>2</u><u>3</u><u>)</u><u> </u><u>x</u><u> </u><u>(</u><u>2</u><u>2</u><u>/</u><u>4</u><u>5</u><u>)</u>
<u>=</u><u> </u><u>8</u><u>8</u><u>/</u><u>3</u><u>4</u><u>5</u>