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3 years ago

Foreign object obstruction to the airway in the adult usually occurs

1 answer:

Citrus2011 [14]3 years ago

7 0

Foreign object obstruction in the airway in adults usually occurs during meals due to choking. Airway obstruction happens when there is something that blocks the airway resulting in difficulty in breathing. The most common technique used when a person is identified having foreign object obstruction is called the Heimlich Maneuver.

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To assist in nutrition screening in the community, the local senior center has developed a screen to help them identify individu

Ludmilka [50]

Answer:

A) Eats alone most of the time

Explanation:

It has been confirmed that eating alone often is harmful to health. Eating alone can increase the risk of obesity in adult citizens, but it can also lead to malnutrition, as many people feel no stimulation to eat alone. For this reason, to help with nutritional screening in the community, the local senior center that has developed a screen to help them identify individuals at high risk for malnutrition should use the "eat alone most of the time" factor as a risk factor for malnutrition.

7 0

4 years ago

Differentiate the following functions (i) x(1+x)^3

statuscvo [17]

Answer:

$\displaystyle y' = (1 + x)^2(4x + 1)$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Functions
Function Notation
Factoring

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Explanation:

Step 1: Define

Identify

y = x(1 + x)³

Step 2: Differentiate

Product Rule [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]$
Derivative Property [Addition/Subtraction]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])$
Basic Power Rule: $\displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})$
Simplify: $\displaystyle y' = (1 + x)^3 + 3x(1 + x)^2$
Factor: $\displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]$
Combine like terms: $\displaystyle y' = (1 + x)^2(4x + 1)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago

What scenario is the best example of public health promotion

Tasya [4]

Do you have any choices ?

4 0

3 years ago

More help, please! I upvote every response. :D

ikadub [295]

False flexibity is known to be beneficial for flexibility

8 0

3 years ago

What does regular participation in sports do to your body

r-ruslan [8.4K]

Answer:

Being active regularly, offers a range of health benefits: Increases flexibility and movement and improves joint mobility. Improves co-ordination, movement and balance – helps to reduce the risk of falls and injury.

Explanation:

Hope this help

3 0

3 years ago

Read 2 more answers