I´d say "d" is the distance from the eye to the wall.
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
Now you have 3 ecs and 3 variables.
alfa,B and "d"
Answer:
x=8
Step-by-step explanation:
4 ^(1/2x) = 256
Rewriting 256 as a power of 4
4 ^(1/2x) = 4^4
Since the bases are the same, the exponents are the same
1/2x = 4
Multiply each side by 2
1/2x *2 = 4*2
x=8
Answer:
Area of the rhombus ABCD = 16 square units
Step-by-step explanation:
Area of a rhombus = 
From the graph attached,
Diagonal 1 = Distance between the points A and C
Diagonal 2 = Distance between the points B and D
Length of a segment between (x₁, y₁) and (x₂, y₂) = 
Diagonal 1 (AC) = 
= 4 units
Diagonal 2(BD) = 
= 8 units
Now area of the rhombus ABCD = 
= 
= 16 units²
Therefore, area of the given rhombus is 16 units².
It's the third one because as Kendall spent more time training or running, their distance increased
Answer:
3u-15
Step-by-step explanation:
3(u-5)
Just multiply 3 by both of the numbers inside the parentheses and we get: 3u-15
