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Phoenix [80]
4 years ago
8

Based on lewis structure analysis, what is the formal charge of the central atom in clf3

Chemistry
1 answer:
MArishka [77]4 years ago
4 0
Formal Charge is calculated as, Lewis structure is attached below,

Formal Charge  =  [# of valence electrons] - [electrons in lone pairs + 1/2 the                                     number of bonding electrons]

# of valence electrons of Cl  = 7

electrons in lone pairs  =  4

number of bonding electrons  =  6

Formal Charge  =  [7] - [4 + 6/2]

Formal Charge  =  [7] - [4 + 3]

Formal Charge  =  [7] - [7]

Formal Charge  =  0

Result:
           Formal charge on Cl in ClF₃ is zero.

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3 years ago
What is the chemical formula of water?<br> O N20<br> O H20<br> O NH3<br> O HO3
svet-max [94.6K]

Answer:

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3 0
3 years ago
Read 2 more answers
The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.320 M NaOH. What is the init
yan [13]

This question is incomplete, the complete question is;

The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator.

The buret contains 0.320 M NaOH,

It requires 11.2 mL of the NaOH solution to reach the end point of the titration

What is the initial concentration of HCI?

Answer:  

initial concentration of HCl is 0.3584 M

Explanation:

Given that;

the reaction between HCl and NaOH is 1:1 molar

HCl(aq) + NaOH(aq) -------> NaCl(aq) + H2O(l)

we know that molarity is the number of moles of solute per liter of solution

so moles of NaOH consumed

= ( 0.320 mol / 1000ml) × 11.2ml

= 0.003584 mol

now

0.003584 moles of NaOH reacts with 0.003584 moles of HCl

moles of HCl present in the 10.0ml solution = 0.003584 mol

therefore the initial concentration of HCl

= ( 0.003584 mol / 10.0ml )× 1000ml

= 0.3584 M

the initial concentration of HCl is 0.3584 M

5 0
4 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
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