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2 years ago

What is the number “4” in SiCl4? a subscript a coefficient a product a reactant

Chemistry

2 answers:

photoshop1234 [79]2 years ago

8 0

Answer: A) subscript

Explanation:

8_murik_8 [283]2 years ago

6 0

Answer:

A.) a subscript

Explanation:

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A sample of hydrogen gas at a pressure of 977 mm Hg and a temperature of 32 °C, occupies a volume of 11.3 liters. If the gas is

IrinaK [193]

Answer : The volume of gas sample will be, 9.93 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=11.3L\\T_1=32^oC=(32+273)K=305K\\V_2=?\\T_2=-5^oC=(-5+273)K=268K$

Now put all the given values in above equation, we get:

$\frac{11.3L}{305K}=\frac{V_2}{268K}\\\\V_2=9.93L$

Therefore, the volume of gas sample will be, 9.93 L

6 0

3 years ago

5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7

slega [8]

Answer:

The molecular formula = C6H6

Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

CO2 = 16.39 grams

H2O = 3.46 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16. 0g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 = 0.385 moles

Moles C = 1* 0.385 = 0.385 moles

Moles H2O = 3.46 grams / 18.02

Moles H2O = 0.192 moles

Moles H = 2* 0.192 = 0.384 moles

Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

Mass C = 4.62 grams

Mass H = 0.39 grams

Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

The empirical formula is CH

This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

n = 78 g/mol / 13 g/mol

n = 6

The molecular formula = 6*(CH) = C6H6

4 0

3 years ago

what is the ratio of the rate of effusion of helium (atomic mass 4.00 amu) to that of oxygen gas (molecular mass 32.0 amu)?

nignag [31]

Answer:

3 : 1

Explanation:

Let the rate of He be R1

Molar Mass of He (M1) = 4g/mol

Let the rate of O2 be R2

Molar Mass of O2 (M2) = 32g/mol

Recall:

R1/R2 = √(M2/M1)

R1/R2 = √(32/4)

R1/R2 = √8

R1/R2 = 3

The ratio of rate of effusion of Helium to oxygen is 3 : 1

8 0

3 years ago

Which change in the sun’s gravity would occur if the sun’s mass were reduced by one-half?(1 point)

Kisachek [45]

Answer:

Gravity or the gravitational force is defined as the force of attraction occurring between all states of matter. The sun’s gravity, mass, and radius plays a crucial role in the properties of the Sun.

Explanation:

The gravity of an object can be determined using the formula:

$\text{g}&=\frac{\text{GM}}{\text{R}^{2} }}$

Now, according to the question, the mass of the sun is halved, which will be written as:

$\text{g}&=\frac{\text{G}\frac{\text{M}}{2}}{\text{R}^{2} }}$

Thus, according to the equation, the mass of an object is directly proportional to the gravitational field. since, the mass of the Sun is reduced to half, the gravity of the Sun will be halved.

8 0

3 years ago

Read 2 more answers

Using the table on the right, complete each calculation by typing in the correct answer.

Pavel [41]

Answer:

13,200 mL

Explanation:

multiply by 1000 to go from L to mL

8 0

3 years ago