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goldfiish [28.3K]
3 years ago
7

Which statement about liquid state of matter is true?

Chemistry
1 answer:
serious [3.7K]3 years ago
4 0
The answer is A! Let me know if I was correct
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the trunk of a certain tree is 50 cm thick. Each year it gets thicker by 1 cm. How thick will the tree trunk be in 50 years
Mama L [17]
100 centimeters thick

Starting thickness was 50 cm
1 cm every 50 years= 1x50
1x50=50
Old thickness + New thickness= 50 + 50 = 100 cm
:)
5 0
3 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
saveliy_v [14]

3 Ca(OH)2 + 2 H3PO4 => 1 Ca3(PO4)2 + 6 H2O

4 0
3 years ago
Which type of bond, geometry and polarity of copper sulphate II ?​
ElenaW [278]
<h3>Sulfate takes two Copper atoms and gains negative valence charge,whereas the Copper gains a positive valence charge.The Sulfate is bonded in covalent bonds of polarity, Oxygen having the higher electronegativity, and therefore pulling the electrons closer to it's nucleus than to Sulfur's nucleus.</h3>

6 0
3 years ago
Which is correct if 15,390,000 is rounded to two significant figures?
BARSIC [14]

Answer:

Explanation:

Remark

This is one of those questions that you need the choices. You can't tell what you should enter. For example, in scientific notation, you would get 1.5*10^7.

Or you could keep it as an integer and round to two places 150,000,000,

I would pick scientific notation if you know how to use it. Otherwise use the interger format.

7 0
2 years ago
How old is a bone if it now .3125 of C-14 when it originally had 80.0g of C-14
Taya2010 [7]
<h3>Answer:</h3>

42960 years

<h3>Explanation:</h3>

<u>We are given;</u>

  • Remaining mass of C-14 in a bone is 0.3125 g
  • Original mass of C-14 on the bone is 80.0 g
  • Half life of C-14 is 5370 years

We are required to determine the age of the bone;

  • Using the formula;
  • Remaining mass = Original mass × 0.5^n , where n is the number of half lives.

Therefore;

0.3125 g = 80.0 g × 0.5^n

3.90625 × 10^-3 = 0.5^n

  • Introducing logarithm on both sides;

log 3.90625 × 10^-3 = n log 0.5

Solving for n

n = log 3.90625 × 10^-3 ÷ log 0.5

   = 8

  • Therefore, the number of half lives is 8
  • But, 1 half life is 5370 years
  • Therefore;

Age of the rock = 5370 years × 8

                          = 42960 years

Thus, the bone is 42960 years old

7 0
4 years ago
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