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Alina [70]
3 years ago
12

An object is found to have a mass of 54.3 g. Find the object’s density, if its volume is 47.18 cm3

Chemistry
1 answer:
Schach [20]3 years ago
8 0

Answer:

d≈ 1.15 g/cm^3

Explanation:

The density of an object can be found by dividing the mass over the volume.

d= m/v

The mass of the object is 54.3 grams and the volume is 47.18 cubic centimeters.

m= 54.3 g

v= 47.18 cm^3

Substitute the values into the formula.

d= 54.3 g/ 47.18 cm

Divide.

d= 1.150911403136922 g/cm^3

Let’s round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 5 in the hundredth place.

d ≈ 1.15 g/cm^3

The density is about 1.15 grams per cubic centimeter.

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<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
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<u>Stoichiometry</u>

  • Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] 6.7 L O₂

[Solve] g O₂

<u>Step 2: Identify Conversions</u>

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Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 6.7 \ L \ O_2(\frac{1 \ mol \ O_2}{22.4 \ L \ O_2})(\frac{44.01 \ g \ O_2}{1 \ mol \ O_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 13.1637 \ g \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

13.1637 g CO₂ ≈ 13 g CO₂

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