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Ronch [10]
3 years ago
7

Part 2 please and explain please

Chemistry
1 answer:
vekshin13 years ago
6 0

1) 7.15 * 10^6

since the exponent of the scientific notation is positive, move 6 places to the right.

so, <em>7.15 * 10^6 = 7150000</em>

2) 3.03 * 10^-8

Since the exponent of the scientific notation is negative, move the decimal point 8 places to the left.

so,<em> 3.03 * 10^-8 = 0.0000000303</em>

<em />

3)<em> </em>4.9 * 10^-1

since the exponent of the scientific notation is negative, move 1 decimal place to the left.

so,<em> 4.9 * 10^-1 = 0.49</em>

<em />

4) 2.886 * 10^5

since the exponent of the scientific notation is positive, move 5 decimal places to the right.

so,<em> 2.886 * 10^5 = 288600</em>

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Answer: its C just got it right

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How many grams of kclo3 are needed to make 30.0 grams of kcl
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The mass of  potassium chlorate, KClO₃ needed to produce 30 grams of potassium chloride, KCl is 49.33 grams

<h3>Balanced equation </h3>

2KClO₃ —> 2KCl + 3O₂

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Mass of KClO₃ from the balanced equation = 2 × 122.5 = 245 g

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SUMMARY

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

<h3>How to determine the mass of KClO₃ needed </h3>

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

Therefore,

30 g of KCl will be obtained from = (30 × 245) / 149 = 49.33 g of KClO₃

Thus, 49.33 g of KClO₃ are needed for the reaction

Learn more about stoichiometry:

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7 0
2 years ago
The solution to be tested in this experiment must be buffered to ph of 10. If the ph were considerably higher, such as 12, how w
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For a solution to be tested in this experiment and must be buffered to pH of 10,  the [OH-] change will be, The hydroxide concentration would be higher and the formation of insoluble hydroxide salts with Mg^2 and Ca^2 would cause the determined concentration of water hardness to be too low.

<h3>What would be the [OH-] change?</h3>

Generally, the equation for the  Total hardness is mathematically given as

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Where

D=\frac{molarity}{0.01}

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2 years ago
What is the ph of a 7.5×10-3m oh- solution? <br><br> ph=?
BlackZzzverrR [31]
We will assume complete dissociation.
Since we have the molarity of OH solution, we can calculate the p(OH) as follows:
p(OH) = -log(molarity of OH) = -log(<span>7.5×10-3) = 2.1249

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4 years ago
Uplift occurs at a rate of 0.1 m per 1,000 years. How much will the uplift change over 100,000 years? 10 m 100 m 1,000 m 10,000
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<h3>Answer:</h3>

= 10 m

<h3>Explanation:</h3>

We are given;

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