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Ronch [10]
3 years ago
7

Part 2 please and explain please

Chemistry
1 answer:
vekshin13 years ago
6 0

1) 7.15 * 10^6

since the exponent of the scientific notation is positive, move 6 places to the right.

so, <em>7.15 * 10^6 = 7150000</em>

2) 3.03 * 10^-8

Since the exponent of the scientific notation is negative, move the decimal point 8 places to the left.

so,<em> 3.03 * 10^-8 = 0.0000000303</em>

<em />

3)<em> </em>4.9 * 10^-1

since the exponent of the scientific notation is negative, move 1 decimal place to the left.

so,<em> 4.9 * 10^-1 = 0.49</em>

<em />

4) 2.886 * 10^5

since the exponent of the scientific notation is positive, move 5 decimal places to the right.

so,<em> 2.886 * 10^5 = 288600</em>

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the chemical compound C2F4 is used to make PTEE (Teflon). How manyC2F4 molecules are in 485 kilograms of this material?
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Answer:

molecules=2.92x10^{27}moleculesC_2F_4

Explanation:

Hello,

In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:

molecules=485kgC_2F_4*\frac{1000gC_2F_4}{1kgC_2F_4} *\frac{1molC_2F_4}{100gC_2F_4}*\frac{6.022x10^{23}molecules C_2F_4}{1molC_2F_4}  \\\\molecules=2.92x10^{27}moleculesC_2F_4

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3 years ago
If 57.3 l of 0.497 m koh is required to completely neutralize 39.5 l of a CH3COOH solution. What is the molarity of the acetic a
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The molarity of the solution will be 0.72 m.

The majority of reactions take place in solutions, making it crucial to comprehend how the substance's concentration is expressed in a solution when it is present. The number of chemicals in a solution can be stated in a variety of ways, including.

The symbol for it is M, and it serves as one of the most often used concentration units. Its definition states how many moles of solute there are in a liter of solution.

Given data:

V_{1} =57.3 L\\V_{2} = 39.5 L\\M_{1} = 0.497 m\\\\M_{2} = ?

Molarity can be determined by the formula:

M_{1} V_{1} = M_{2} V_{2}

where, M is molarity and V is volume.

Put the value of given data in above equation.

57.3 × 0.497 m = M × 39.5 L

M = 0.72 m

Therefore, the molarity of the solution will be 0.72 m

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Flammable gases are gases that have the tendency to <u>explode (burst into flames)</u> when they come in contact with the <u>appropriate quantities of air, oxygen, or any suitable oxidant.</u>

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Devices that mix air or oxygen with flammable gasses cannot be used unless approved by an <u>authorized or approved personnel.</u>

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  • Examples of flammable gases are hydrocarbons such as <u>Propane, Acetylene</u>, e.t.c.

  • Flammable gases are dangerous to humans and the environment and if they are not handled properly, can cause severe damages and even death.

  • During the preparation and usage of flammable gases, safety precautions should be properly enforced such as the <u>wearing of appropriate safety gear and goggles</u>.

  • Devices that mix air or oxygen with flammable gases cannot be used unless approved by an <u>authorized or approved personnel.</u>

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