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Firdavs [7]
3 years ago
7

Colligative properties include __________ the freezing point, _____________ the vapor pressure, and ___________ the boiling poin

t. Which of the following sequences of words correctly fills in the blanks?
a) raising, lowering, loweringb) raising, raising, loweringc) lowering, raising, loweringd) lowering, lowering, raising
Chemistry
2 answers:
MrMuchimi3 years ago
7 0
Colligative properties include lowering the freezing point, lowering the vapor pressure, and raising the boiling point.

pashok25 [27]3 years ago
3 0

The answer is: d) lowering, lowering, raising.

The vapor pressure depression (lowering), freezing point depression (lowering) and the boiling point elevation (raising) are the colligative properties od solution.

For example pure water has lower boiling point than solution of water and some salt.

The higher is the molarity of the solution, the lower is freezing point.

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A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Evgesh-ka [11]

Answer:

The answer to your question is   P2 = 0.78 atm

Explanation:

Data

Temperature 1 = T1 = 263°K                 Temperature 2 = T2 = 298°K

Volume 1 = V1 = 24 L                             Volume 2 = V2 = 35 L

Pressure 1 = P1 = 1                                  Pressure 2 = P2 = ?

Process

1.- To solve this problem use the Combined gas law

                          P1V1/T1 = P2V2/T2

-Solve for P2

                           P2 = P1V1T2 / T1V2

-Substitution

                          P2 = (1)(24)(298) / (263)(35)

-Simplification

                          P2 = 7152 / 9205

-Result

                          P2 = 0.777

   or                    P2 = 0.78 atm

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3 years ago
Gas is heated from 480. K to 750. K and the pressure is kept constant, what final volume would result if the original volume was
attashe74 [19]
Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
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Parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
Substituting the values in the equation
267 L/ 480 K = V / 750 K
V = 417 L
Final volume is 417 L
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