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FrozenT [24]
3 years ago
11

What is the mole fraction of ethanol in a solution of 3.00 moles of ethanol and 5.00 moles of water?

Chemistry
1 answer:
Rus_ich [418]3 years ago
6 0
If theres a mixture of components we can calculate the mole fraction
mole fraction can be calculated as follows
mole fraction of component = \frac{number of moles of component}{total number of moles of all components }
number of moles of ethanol - 3.00 mol
total number of moles in mixture - 3.00 + 5.00 = 8.00 mol 

mole fraction of ethanol = \frac{3.00 mol}{8.00 mol }
mole fraction of ethanol is 0.375
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Can someone help me on this
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155,500



I did this to the best of my ability. I have a hard time comprehending things sometimes so I’m so so so sorry if it’s wrong
8 0
3 years ago
Pb(SO4)2 + 4 LiNO3 → Pb(NO3)4 + 2 Li2SO4
Anvisha [2.4K]

Answer:

4.5 moles of lithium sulfate are produced.

Explanation:

Given data:

Number of moles of lead sulfate = 2.25 mol

Number of moles of lithium nitrate = 9.62 mol

Number of moles of lithium sulfate = ?

Solution:

Chemical equation:

Pb(SO₄)₂ + 4LiNO₃      →     Pb(NO₃)₄ + 2Li₂SO₄

Now we will compare the moles of lithium sulfate with lead sulfate and lithium nitrate.

                       Pb(SO₄)₂        :         Li₂SO₄

                            1                :             2

                          2.25           :          2/1×2.25 = 4.5 mol

                       LiNO₃            :             Li₂SO₄

                           4                :                2

                           9.62           :             2/4×9.62 = 4.81 mol

Pb(SO₄)₂  produces less number of moles of Li₂SO₄ thus it will act as limiting reactant and limit the yield of  Li₂SO₄.      

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3 years ago
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3 0
3 years ago
Calculate the approximate volume of a 0.6000mol sample of gas at 288.15K and a pressure of 1.10atm.
11111nata11111 [884]

Answer:

The volume of the sample of the gas is found to be 12.90 L.

Explanation:

Given pressure of the gas = P = 1.10 atm

Number of moles of gas = n = 0.6000 mole

Temperature = T = 288.15 K

Assuming the volume of the gas to be V liters

The ideal gas equation is shown below

\textrm{PV} =\textrm{nRT} \\1.10 \textrm{ atm}\times V \textrm{ L} = 0.6000 \textrm{ mole}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 288.5\textrm{K} \\\textrm{V} = 12.90 \textrm{ L}

Volume occupied by gas = 12.90 L

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3 years ago
Why is sodium metal (very soft and can cut easily) stored under oil?
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7 0
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