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3 years ago

What is the mole fraction of ethanol in a solution of 3.00 moles of ethanol and 5.00 moles of water?

1 answer:

6 0

If theres a mixture of components we can calculate the mole fraction
mole fraction can be calculated as follows
mole fraction of component = $\frac{number of moles of component}{total number of moles of all components }$
number of moles of ethanol - 3.00 mol
total number of moles in mixture - 3.00 + 5.00 = 8.00 mol

mole fraction of ethanol = $\frac{3.00 mol}{8.00 mol }$
mole fraction of ethanol is 0.375

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What is the mass of the ethanol that exactly fills a 200.0 mL container? The density of ethanol is 0.8 g/mL. please help

Naddik [55]

160.0g

Mass =volume x density = 200.0 mL x 0.8 g/mL= 160.0 g

7 0

3 years ago

Final volume of Argon gas:

DerKrebs [107]

Answer:

6.78 × 10⁻³ L

Explanation:

Step 1: Write the balanced equation

Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)

Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)

At STP, 1 mole of H₂O(g) has a volume of 22.4 L.

0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol

Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)

The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.

Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃

At STP, 1 mole of NH₃(g) has a volume of 22.4 L.

3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L

3 0

3 years ago

Calculate the percent composition of the following:<br><br> A. VO3<br><br> B. V2O5

tino4ka555 [31]

A) Answer is: 51.48% V and 48.52% O.

Ar(V) = 50.94; atomic weight of vanadium.

Ar(O) = 16; atomic weight of oxygen.

Ar(VO₃) = 50.94 + 3 · 16.

Ar(VO₃) = 98.94; molecular weight of vanadium (VI) oxide.

ω(V) = Ar(V) ÷ Ar(VO₃) · 100%.

ω(V) = 51.48%; the percent composition of vanadium.

ω(O) = 100% - 51.48%.

ω(O) = 48.52%; the percent composition of oxygen.

B) Answer is: 67.80% V and 32.20% O.

Ar(V) = 50.94; atomic weight of vanadium.

Ar(O) = 16; atomic weight of oxygen.

Ar(V₂O₅) = 2 · 50.94 + 5 · 16.

Ar(V₂O₅) = 149.88; molecular weight of vanadium (V) oxide.

ω(V) = 2 · Ar(V) ÷ Ar(V₂O₅) · 100%.

ω(V) = 67.80%; the percent composition of vanadium.

ω(O) = 100% - 67.80%.

ω(O) = 32.20%; the percent composition of oxygen.

4 0

3 years ago

According to Frank, what is the “10 second rule"?

Lelechka [254]

Answer:

The first option, aka Opick it up off the gound within 10 seconds, and it's o.k. to eat

Explanation:

The 10 second rule is a rule when you drop foods, but if you get it off the floor under 10 seconds, you can eat it.

Did you know that food picked up under 10 seconds and after 10 seconds has almost the same number of bacterias? The 10 second rule is basically worthless.

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2 years ago

A. The structure of [NO3]- is either trigonal planar or trigonal pyramidal draw both possible structures and determine the point

Ostrovityanka [42]

Answer:

Look at the picture.

Explanation:

For planar anion point group is D3h. For trigonal piramidal point group is C3v.

On picture 2 and 3 are the tables for each point group. Irreducible representations its the horizontal rows in tables. Where you see x, y and z it's translation of p-orbitals. Where you see R - it's rotations.

6 0

3 years ago