The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the
1 answer:
Answer:
The proportion of flanges that exceeds 0.99 millimeters is 0.6
Explanation:
Given;
integral range of [0.95, 1.05]
Let X be a variable with uniform distribution over the given range.
1 - 0.95 = 0.05, 1.05 - 1 = 0.05
interval = 10 - 0.5 = 9.5
F(x) = 10x + 9.5
When, X exceeds 0.99 millimeters, then the proportion of flanges will be;
P (X > x) = 1 - F(x)
P( X > 0.99 ) = 1 - 10(0.99) + 9.5
P( X > 0.99 ) = 0.6
Therefore, the proportion of flanges that exceeds 0.99 millimeters is 0.6
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