Some curious students hold a rolling race by rolling four items down a steep hill. The four items are a solid homogeneous sphere
, a thin spherical shell, a solid homogeneous cylinder and a hoop with all its mass concentrated on the hoop's perimeter. All of the objects have the same mass and start from rest. Assume that the objects roll without slipping and that air resistance and rolling resistance are negligible. For each statement below, select True or False.
a) Upon reaching the bottom of the hill, the hoop will have a larger rotational kinetic energy than any of the other objects will when they reach the bottom of the hill.
A: True B: False
b) The hoop reaches the bottom of the hill before the homogeneous cylinder.
A: True B: False
a) Upon reaching the bottom of the hill, the hoop will have a larger rotational kinetic energy than any of the other objects will when they reach the bottom of the hill.
A: True B: False
b) The hoop reaches the bottom of the hill before the homogeneous cylinder.
A: True B: False
1 answer:
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Answer:
temperature at 326.44 K system achieve equilibrium
Explanation:
given data
mass of block of ice = 4.6 kg
temperature = 263 K
thermal contact = 15.7-kg
specific heat of silver cAg = 233 J/kg-K
initially temperature = 1052 K
to find out
what temperature will the system achieve equilibrium
solution
first we consider final temperature of the system is T
we know that specific heat of water (C w) = 4186 J(kg K)
and
specific heat of ice ( C i ) = 2030 J/(kg K)
and
latent heat of fusion of ice ( Lf ) = 3.33 × J/kg
and we know that system is insulated
so heat lost by silver = heat generated by ice .................1
so we can say
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
put here value we get
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
15.7 × 233 × ( 1052 - T ) = 4.6 × 2030 × 10 + 4.6 × 3.33 × + 4.6 × 4286 × ( T - 273 )
solve we get
T = 326.44 K
so temperature at 326.44 K system achieve equilibrium