Answer:
refer to this site it has information about limiting reactant -
https://chem.libretexts.org/Bookshelves/Inorganic_Chemistry/Supplemental_Modules_(Inorganic_Chemistry)/Chemical_Reactions/Limiting_Reagents
Answer:
She turned back at the point at which she forgot she left her briefcase. If this isn't the correct answer, please be more specific in the question.
Explanation:
Answer:
N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)
Explanation:
The half reaction for the reaction for the reduction of gaseous nitrogen to aqueous hydrazine is;
N₂(g) → N₂H₄(aq)
The balancing the atoms in the half reaction. Hydrogen atom is balanced by adding hydrogen ions (H⁺)
We have;
N₂(g) + 4H⁺(aq) → N₂H₄(aq)
Then we balance the charge on both sides by adding electrons where the positive charge is greater;
we have;
N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)
Mole number of 75 g is 0.4 mol. NO2 is 0.8 mol and is 36.8 g.
Answer:
84.27 g
Explanation:
<em>How many grams of hydrogen are in 10.45 moles of C₃H₈?</em>
Step 1: Calculate the moles of atoms of hydrogen
The molar ratio of C₃H₈ to H is 1:8.
10.45 mol C₃H₈ × 8 mol H/ 1mol C₃H₈ = 83.60 mol H
Step 2: Calculate the mass corresponding to 83.60 moles of hydrogen
The molar mass of hydrogen is 1.008 g/mol.
83.60 mol × 1.008 g/mol = 84.27 g
