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Novay_Z [31]
3 years ago
12

How does the equilibrium change to counter the removal of A in this reaction? A + B ⇌ AB The equilibrium . Simultaneously, there

’s an increase in the reaction.
Chemistry
2 answers:
kykrilka [37]3 years ago
7 0

Based on Le Chatelier's principle, if the equilibrium of a system is disturbed by changing the temperature, pressure or concentration, then it will shift in a direction to undo the effect of the induced change.

The given equilibrium is:

A + B ↔ AB

Removal of the reactant A implies that the concentration of A has decreased, therefore the equilibrium will shift in a direction to produce more of A. Thus, it will shift to the left and the rate of the reverse or backward reaction will increase.

Ipatiy [6.2K]3 years ago
4 0

AnsweR

The equilibrium SHIFTS LEFT. Simultaneously, there’s an increase in the REVERSE reaction.

Explanation:

A + B ⇌ AB

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14. An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km
emmainna [20.7K]

Answer:

27 min

Explanation:

The kinetics of an enzyme-catalyzed reaction can be determined by the equation of Michaelis-Menten:

v = \frac{vmax[S]}{Km + [S]}

Where v is the velocity in the equilibrium, vmax is the maximum velocity of the reaction (which is directed proportionally of the amount of the enzyme), Km is the equilibrium constant and [S] is the concentration of the substrate.

So, initially, the velocity of the formation of the substrate is 12μmol/9min = 1.33 μmol/min

If Km is a thousand times smaller then [S], then

v = vmax[S]/[S]

v = vmax

vmax = 1.33 μmol/min

For the new experiment, with one-third of the enzyme, the maximum velocity must be one third too, so:

vmax = 1.33/3 = 0.443 μmol/min

Km will still be much smaller then [S], so

v = vmax

v = 0.443 μmol/min

For 12 μmol formed:

0.443 = 12/t

t = 12/0.443

t = 27 min

7 0
3 years ago
How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol
mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

2Al + 3Cu{(NO_3)}_2  \rightarrow 2Al{(NO_3)}_3 +3 Cu

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

Al \rightarrow Al^{3+} + 3e^-

And copper goes from +2 to 0

Cu^{2+} + 2e^-\rightarrow Cu

On balancing the number of electrons we get:

For 1 mole of Al 6e^- is required.

Therefore for 2 moles of Al,

Total (2\times6)F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

brainly.com/question/27985929

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4 0
1 year ago
Sarah is in her chemistry lab doing an experiment. When she goes to take the mass of the chemical she is working with, she disco
cupoosta [38]

Answer:

10 x 5 = 50

Explanation:

50 is the mass of her chemical.

7 0
3 years ago
What is the primary cause of diffusion? 1.that some substances can dissolve in solvents 2.heat added to a substance 3.random int
shusha [124]
Diffusion : a process in which molecules intermingle as a result of  their kinetic energy of random motion
The primary cause of diffusion is : 3. Random internal motion of atoms and molecules

hope this helps
6 0
3 years ago
Read 2 more answers
A chemistry teacher is able to grade chemistry labs at a rate of 5 labs for every 3 minutes. They need to grade 165 labs how man
PIT_PIT [208]

Answer:

1.65hr

Explanation:

Given parameters:

Number of labs  = 5 labs

 Time taken  = 3 minutes

Unknown:

Time taken in hours to grade 165 labs  = ?

Solution:

Let us find the rate of the teacher;

  Rate  = \frac{number of labs}{time}  

  Insert the parameters and solve;

   Rate  = \frac{5}{3}   = 1.67labs/min

Now;

   Time to grade 165 labs  = \frac{number of labs}{rate}  

   Time to grade 165 labs  = \frac{165}{1.67}   = 98.8min

  Since;

               60min = 1hr

               98.8min  = \frac{98.8}{60}   = 1.65hr

3 0
3 years ago
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